5. Shane has $6 more than three times the

Mathematics

1 answer:

maria [59]3 years ago

4 0

Answer:

$31

Step-by-step explanation:

(99 - 6) / 3

You might be interested in

If a function is derivable at a point it is also continous at that point explain why?

Artyom0805 [142]

For a function to have a derivative in a point has to be continuous at the point, that is, it has to be defined at that point, other wise the derivative would be meaningless.

5 0

4 years ago

How to solve an expression with variables in the exponents?

gtnhenbr [62]

Answer:

use logarithms

Step-by-step explanation:

Taking the logarithm of an expression with a variable in the exponent makes the exponent become a coefficient of the logarithm of the base.

You will note that this approach works well enough for ...

a^(x+3) = b^(x-6) . . . . . . . . . . . variables in the exponents

(x+3)log(a) = (x-6)log(b) . . . . . a linear equation after taking logs

but doesn't do anything to help you solve ...

x +3 = b^(x -6)

There is no algebraic way to solve equations that are a mix of polynomial and exponential functions.

Some functions have been defined to help in certain situations. For example, the "product log" function (or its inverse) can be used to solve a certain class of equations with variables in the exponent. However, these functions and their use are not normally studied in algebra courses.

In any event, I find a graphing calculator to be an extremely useful tool for solving exponential equations.

8 0

3 years ago

If the given values in a right triangle are cos A =

Vlad1618 [11]

See the picture attached to better understand the problem

we know that
in the right triangle ABC
cos A=AC/AB
cos A=1/3
so
1/3=AC/AB----->AB=3*AC-----> square----> AB²=9*AC²----> equation 1

applying the Pythagoras Theorem
BC²+AC²=AB²-----> 2²+AC²=AB²---> 4+AC²=AB²----> equation 2

substitute equation 1 in equation 2
4+AC²=9*AC²----> 8*AC²=4----> AC²=1/2----> AC=√2/2
so
AB²=9*AC²----> AB²=9*(√2/2)²----> AB=(3√2)/2

the answer is
the hypotenuse is (3√2)/2