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kotegsom [21]
3 years ago
13

Find the measure of X from the circle below:

Mathematics
1 answer:
Marat540 [252]3 years ago
8 0

Answer: it looks like about 180 degrees

Step-by-step explanation:

sorry if wrong can you help me if right please

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Which equation represents a line that passes through (–9, –3) and has a slope of –6?
larisa [96]

Answer:

y = - 6x - 57

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

here m = - 6, thus

y = - 6x + c ← is the partial equation

To find c substitute (- 9, - 3) into the partial equation

- 3 = 54 + c ⇒ c = - 3 - 54 = - 57

y = - 6x - 57 ← equation of line

4 0
3 years ago
Please tell how to write an expression for this​
BARSIC [14]

Answer:

N is 7 x 7, because there is a order which is the term and number are like being multiplied by the same number for example "1 x 1 =1, 2 x 2 = 4" and so on

Step-by-step explanation:

5 0
3 years ago
Please help me out with this :)
Misha Larkins [42]

Answer:

x = 1

Step-by-step explanation:

Given that y varies directly with x then the equation relating them is

y = kx ← k is the constant of variation

To find k use the condition y = 12 when x = - 2, then

k = \frac{y}{x} = \frac{12}{-2} = - 6, thus

y = - 6x ← equation of variation

When y = - 6, then

- 6 = - 6x ( divide both sides by - 6 )

x = 1

8 0
4 years ago
Hey can someone please help explain and answer this 1 question. There's a picture. Thank you!
g100num [7]
We'll first clear a few points.
1. A hyperbola with horizontal axis and centred on origin (i.e. foci are centred on the x-axis) has equation
x^2/a^2-y^2/b^2=1
(check: when y=0, x=+/- a, the vertices)
The corresponding hyperbola with vertical axis centred on origin has equation
y^2/a^2-x^2/b^2=1
(check: when x=0, y=+/- a, the vertices).

The co-vertex is the distance b in the above formula, such that 
the distance of the foci from the origin, c satisfies c^2=a^2+b^2.
The rectangle with width a and height b has diagonals which are the asymptotes of the hyperbola.

We're given vertex = +/- 3, and covertex=+/- 5.
And since vertices are situated at (3,0), and (-3,0), they are along the x-axis.
So the equation must start with
x^2/3^2.

It will be good practice for you to sketch all four hyperbolas given in the choices to fully understand the basics of a hyperbola.
6 0
3 years ago
Write an equation in slope intercept form with a slope of 1/2 and y-intercept of -7
Pavlova-9 [17]

Answer:

y=1/2x-7

Step-by-step explanation:

The slope is always the number with "x", and the y-intercept is at the end of the equation. In this case, 1/2 is with the "x", and -7 is the y-intercept.

3 0
3 years ago
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