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Ratling [72]
3 years ago
12

A box is created from a sheet of cardboard 20 in. on a side by cutting a square from each corner and folding up the sides. Let x

represent the length of the sides of the squares removed from each corner. Find an expression for the volume of the box in terms of x

Mathematics
1 answer:
Digiron [165]3 years ago
5 0
Assuming the sheet is a square

see diagram
the length will be 20-2x
the width will be 20-2x
and the height will be x

the volume will be (20-2x)(20-2x)(x)

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tresset_1 [31]

Respuesta:839202829 :VVV

5 0
3 years ago
Sandra is showing her work in simplifying (3.3 − 4.2) − 2.8 + 5.7. Identify any error in her work or reasoning. Step 1: (3.3 − 4
julsineya [31]
The answer is correct 
but I think in step 2 that should read the Associative property
8 0
3 years ago
Read 2 more answers
List all the factors of 16 ​
Ronch [10]

Answer:

1,2,4,8,16

Step-by-step explanation:

prime factorization: 2x2x2x2 =16

4 0
3 years ago
On a biased dice the probability of getting 1 is 0.3. The ice is rolled 150 times. How many ones would you expect to roll?
Montano1993 [528]

Answer:  45

=====================================================

Work Shown:

n = number of rolls = 150

p = probability of rolling a "1" = 0.3

n*p = expected number of "1"s that show up out of the 150 rolls

n*p = 150*0.3

n*p = 45

We expect about 45 ones will show up.

8 0
3 years ago
A simple random sample of 110 analog circuits is obtained at random from an ongoing production process in which 20% of all circu
telo118 [61]

Answer:

64.56% probability that between 17 and 25 circuits in the sample are defective.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 110, p = 0.2

So

\mu = E(X) = np = 110*0.2 = 22

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{110*0.2*0.8} = 4.1952

Probability that between 17 and 25 circuits in the sample are defective.

This is the pvalue of Z when X = 25 subtrated by the pvalue of Z when X = 17. So

X = 25

Z = \frac{X - \mu}{\sigma}

Z = \frac{25 - 22}{4.1952}

Z = 0.715

Z = 0.715 has a pvalue of 0.7626.

X = 17

Z = \frac{X - \mu}{\sigma}

Z = \frac{17 - 22}{4.1952}

Z = -1.19

Z = -1.19 has a pvalue of 0.1170.

0.7626 - 0.1170 = 0.6456

64.56% probability that between 17 and 25 circuits in the sample are defective.

4 0
3 years ago
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