Yep! Good job, you did it correctly.
Your y-intercept is equal to the constant of the equation (y-int = -2). Your movement/direction (or rise over run) is equal to the variable. Since your variable is x (which can also be written as 1x) means you move up one and over one (rise over run). This is because 1/1 is equal to 1.
The coordinates of the pre-image of point F' is (-2, 4)
<h3>How to determine the coordinates of the pre-image of point F'?</h3>
On the given graph, the location of point F' is given as:
F' = (4, -2)
The rule of reflection is given as
Reflection across line y = x
Mathematically, this is represented as
(x, y) = (y, x)
So, we have
F = (-2, 4)
Hence, the coordinates of the pre-image of point F' is (-2, 4)
Read more about transformation at:
brainly.com/question/4289712
#SPJ1
Follow pemdas. Evaluate operations in parentheses first.
2*(-7)+14-4
Then multiply
-14+14-4
Then add and subtract from left to right
-14+14=0
0-4=-4
Final answer: -4
Answer:
It is the top right one.
Step-by-step explanation:
Answer:
y = 42
Step-by-step explanation:
Given that y varies directly as x then the equation relating them is
y = kx ← k is the constant of variation
To find k use an ordered pair from the table.
Using x = 2 when y = 12, then
12 = 2k ( divide both sides by 2 )
6 = k
y = 6x ← equation of variation
When x = 7, then
y = 6 × 7 = 42
