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3 years ago

Find the length of KM. Helpppppppppp

Mathematics

1 answer:

AlekseyPX3 years ago

4 0

Answer:

Step-by-step explanation:

KL = 12

LM = 9

12 + 9 = 21

KM = 21

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(9^6 * 7^-9)^-4.<br> Thanks!

Anuta_ua [19.1K]

Answer:

$\frac{7^{36}}{9^{24}}$

Step-by-step explanation:

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1 year ago

Find the first three terms in the expansion , in ascending power of x , of (2+x)^6 and obtain the coefficient of x^2 in the expa

Nataly_w [17]

Answer:

The first 3 terms in the expansion of $(2 + x)^{6}$ , in ascending power of x are,

$64 , 192 \times x^{1} {\textrm{ and }}240 \times x^{2}$

coefficient of $x^{2}$ in the expansion of $(2+x - x^{2})^{6}$ = (240 - 192) = 48

Step-by-step explanation:

$(2+x)^{6}$

= $\sum_{k=0}^{6}(6_{C_{k}} \times x^{k} \times 2^{6 - k})$

= $6_{C_{0}} \times x^{0} \times 2^{6} + 6_{C_{1}} \times x^{1} \times 2^{5} + 6_{C_{2}} \times x^{2} \times 2^{4}$ + terms involving higher powers of x

= $64 + 192 \times x^{1} + 240 \times x^{2}$ + terms involving higher powers of x

so, the first 3 terms in the expansion of $(2 + x)^{6}$ , in ascending power of x are,

$64 , 192 \times x^{1} {\textrm{ and }}240 \times x^{2}$

Again,

$(2+x - x^{2})^{6}$

= $\sum_{k=0}^{6}(6_{C_{k}} \times (2 + x)^{k} \times (-x^{2})^{6 - k})$

Now, by inspection,

the term $x^{2}$ comes from k =5 and k = 6

for k = 5, the coefficient of $x^{2}$ is , $(-32) \times 6$ = -192

for k = 6 , the coefficient of $x^{2}$ is, $6_{C_{2}} \times 2^{4}$ = 240

so, coefficient of $x^{2}$ in the final expression = (240 - 192) = 48

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3 years ago

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3 years ago

In a school, 2/3 of the students study a language.

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Answer:

6:15

Step-by-step explanation:

2/3= 10/15

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6:15

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3 years ago

Which row in the table is closest to the actual solution?

Montano1993 [528]

Answer:

0.8= 2.1448=2.1379

Step-by-step explanation:

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3 years ago

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