9514 1404 393
Answer:
AB = 10
BC ≈ 11.40
Step-by-step explanation:
The distance formula is useful for finding distances between points.
d = √((x2 -x1)² +(y2 -y1)²)
AB = √((18 -10)² +(4 -10)²) = √(8² +(-6)²) = √100
AB = 10
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BC = √((25 -18)² +(-5-4)²) = √(7² +(-9)²) = √130
BC ≈ 11.40
_____
A sketch tool can be useful for finding or checking the answer.
Answer:
4(5x + 6)
Step-by-step explanation:
To start, let's expand things out, as we cannot learn anything from this form. We get 30x + 20 - 10x + 4, or 20x + 24. To find the GCD (Greatest Common Divisor), we take the terms and try to find the number (or term) that divides them. It must be a constant, because of the 24, and 4 goes into 20 and 24. So, our final answer is 4(5x + 6).
Answer:
a) response variable
Step-by-step explanation:
The response variable is the variable that depends on other variables such as the independent or explanatory variable, it is the variable that is being tested. The response variable is also called the dependent variable.
In linear regression, the y variable is referred to as the response variable while the x variable is referred to as the explanatory or independent variable.
In this case the y variable is "the number of times they cough in a day" and this variation depends on the x variable "number of cigarettes a person smokes in a day".
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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