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3 years ago

Find the product

Mathematics

2 answers:

irakobra [83]3 years ago

8 0

Answer:

Step-by-step explanation:

Find the product

2x(x - 3)(x + 2)

OA. 4x - 1

B. 2x3 -X-6 Find the product

2x(x - 3)(x + 2)

OA. 4x - 1 Find the product

2x(x - 3)(x + 2)

OA. 4x - 1

B. 2x3 -X-6

C. 2x3 - 2x2 - 12x

2x3-12x|

B. 2x3 -X-6

C. 2x3 - 2x2 - 12x

2x3-12x|

C. 2x3 - 2x2 - 12x

2x3-12x|Find the product

2x(x - 3)(x + 2)

OA. 4x - 1

B. 2x3 -X-6

C. 2x3 - 2x2 - 12x

2x3-12x|

o-na [289]3 years ago

7 0

Answer:

2x^3 - 2x^2 - 12x

Step-by-step explanation:

2x(x - 3)(x + 2)

= 2x ( x^2 + 2x -3x - 6)

= 2x (x^2 - x - 6)

= 2x^3 - 2x^2 - 12x (answer).

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Find the limit<br> Picture below

pogonyaev

Answer:

a. 4

Step-by-step explanation:

We want to find;

$\lim_{h \to 0} \frac{f(2+h)-f(2)}{h}$

If $f(x)=x^2$ .

$f(2+h)=(2+h)^2$

$f(2+h)=4+4h+h^2$

Also;

$f(2)=2^2$

$f(2)=4$

This implies that;

$\lim_{h \to 0} \frac{4+4h+h^2-4}{h}$

Simplify;

$\lim_{h \to 0} \frac{4h+h^2}{h}$

Factor to get;

$\lim_{h \to 0} \frac{h(4+h)}{h}$

Cancel the common factors.

$\lim_{h \to 0} 4+h$

Substitute h=0 to get

$\lim_{h \to 0} 4+h=4+0=4$

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4 years ago

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Which equations describes the line shown?

LenKa [72]

It should be y=2x-3 since it’s touching -3 on the y axis and the it’s going 2 units up and 1 to the right, making the slope = 2.

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1 year ago

If f(x)=2x-5, find <br><br> a. f(4)<br> b. f(-3)

Vladimir [108]

Replace x in the given equation with each value:

a. f(4) = 2(4) -5

= 8-5

b. (f-3) = 2(-3) - 5

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3 years ago

The relationship between the distance run and the time for Amy can be represented by the equation Y equals 17.45X, where she ran

Kipish [7]

Question;

Assumption:

Let us assume Brandon's running speed is = 18.30 and

Ruben's running speed is = 16.50 and

Answer:

The two equations that can represent the relationship between the meters and second for Brandon and Ruben are;

Brandon → Y₁ = 18.3·X₁ and

Ruben → Y₂ = 16.5·X₂

Step-by-step explanation:

The equation is of the form

Y = 17.45·X

That is Amy ran Y meters in X seconds

Therefore we have

$17.45 = \frac{Y}{X}$ or the value 17.45 is the running speed of Amy

Therefore, where the running speed of Brandon is 18.30 and the running speed of Ruben is 16.50 we have

Y meters ran by Brandon in X seconds given by

Y₁ = 18.3·X₁ and

For Ruben we have Y meters ran in X seconds given by

Y₂ = 16.5·X₂.

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