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3 years ago

In the diagram below, transversal t intersects parallel lines I and m.

Mathematics

1 answer:

Black_prince [1.1K]3 years ago

6 0

Step-by-step explanation:

x+10=116

x=116-110

=106

x=106

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Which could be the function graphed below?

iren [92.7K]

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Answer:

(a) f(x) = √x -2

Step-by-step explanation:

The square root function has no horizontal shift, so the expression under the radical is simply x with no added terms. There is only one such answer choice, which also shows the necessary translation downward by an added negative constant.

$f(x)=\sqrt{x}-2$

5 0

3 years ago

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For what values of x and y are the triangles to the right congruent by HL?

denis23 [38]

Yes it is hl because thats what it is

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3 years ago

Determine whether the statement is true or false. If it is true, explain why. If it is false, explain why or give an example tha

ioda

True.

You're allowed to move stuff around. Dogs of the AMS.

$y' = 3y - 2x + 6xy - 1 \\
y' = 3y + 6xy - 2x - 1 \\
dy/dx= 3y(1 + 2x) - (2x + 1) \\
dy/dx = 3y(1 + 2x) - (1 + 2x) \\
\frac{dy}{dx} = (3y - 1)(1 + 2x) \ \Rightarrow\ \dfrac{dy}{3y-1} = (1 + 2x) dx$

We wrote it in the form dy/dx = g(x) f(y) so this is separable.

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3 years ago

Solve the following question

nydimaria [60]

9514 1404 393

Answer:

π/3

Step-by-step explanation:

The given integral does not exist. We assume there is a typo in the upper limit, and that you want the integral whose upper limit is (√3)/2.

It is convenient to make the substitution ...

x = sin(y) . . . . so, y = arcsin(x)

dx = cos(y)·dy

Then the integral is ...

$\displaystyle\int_0^{\sqrt{3}/2}{\dfrac{\cos{y}}{\sqrt{1-\sin^2{y}}}}\,dy=\int_0^{\sqrt{3}/2}{dy}=\left.\arcsin{x}\right|\limits_0^{\sqrt{3}/2}\\\\=\arcsin{(\sqrt{3}/2)}=\boxed{\dfrac{\pi}{3}}$

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3 years ago

Find the values of y = r(x) = ∛x for

eduard

We're being asked to find the values of y for $\sqrt[3]{x}$ for specific values of x. Basically, we are taking the cube roots of these numbers.

$r(-2.197) = \sqrt[3]{-2.197} = -1.3\\\\ r(-1.331) = \sqrt[3]{-1.331} = -1.1\\\\ r(0) = \sqrt[3]{0} = 0 \\\\ r(1.331) = \sqrt[3]{1.331} = 1.1\\\\r(2.197) = \sqrt[3]{2.197} = 1.3\\\\r(-3.375) = \sqrt[3]{-3.375} = 1.5\\\\r(4.913) = \sqrt[3]{4.913} = 1.7\\\\$

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4 years ago

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