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o-na [289]
3 years ago
6

Factor out the coefficient of the variable. 3.4c+10.2

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
4 0

Answer:

1.7(2c+6)

Step-by-step explanation:

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a cell phone battery uses 1/3 of its charge in 3/8 of a day. How much charge will it use in one day?​
brilliants [131]

\bf \begin{array}{ccll}charge&day\\\cline{1-2}\frac{1}{3}&\frac{3}{8}\\\\x&1\end{array}\implies \cfrac{~~\frac{1}{3}~~}{x}=\cfrac{~~\frac{3}{8}~~}{1}\implies \cfrac{~~\frac{1}{3}~~}{\frac{x}{1}}=\cfrac{3}{8}\implies \cfrac{1}{3}\cdot \cfrac{1}{x}=\cfrac{3}{8}\\\\\\\cfrac{1}{3x}=\cfrac{3}{8}\implies 8=9x\implies \cfrac{8}{9}=x

3 0
3 years ago
What is 62 divided by 0.25
Semenov [28]
62 divided by 0.25 is 248
3 0
3 years ago
The radioactive isotope radium has a half-life of 1,600 years. The mass of a 100-gram sample of radium will be______ grams after
Olenka [21]
To solve this we are going to use the half life equation N(t)=N_{0} e^{( \frac{-0.693t}{t _{1/2} }) }
Where:
N_{0} is the initial sample
t is the time in years
t_{1/2} is the half life of the substance
N(t) is the remainder quantity after t years 

From the problem we know that:
N_{0} =100
t=200
t_{1/2} =1600

Lets replace those values in our equation to find N(t):
N(200) =100e^{( \frac{(-0.693)(200)}{1600}) }
N(200)=100e^{( \frac{-138.6}{1600} )}
N(200)=100e^{-0.086625}
N(200)=91.7

We can conclude that after 1600 years of radioactive decay, the mass of the 100-gram sample will be 91.7 grams.

8 0
3 years ago
Deena has 4 pairs of of white socks , 3 pairs of black sock, 1 pair of red socks, and 2 pairs of Navy socks in her drawer each p
VikaD [51]

Answer:

2/5

Step-by-step explanation:

Ok there are 4+3+1+2 pairs of socks in all... Aka 10 sock pairs in all.

There are 4 white pairs.  So the probability she selects a white pair is 4/10.

4/10 can be reduced to 2/5.

7 0
2 years ago
Read 2 more answers
Im having trouble figuring out the missing length and solving this, can I have some help?
belka [17]
I think the answer is 17
8 0
2 years ago
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