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kaheart [24]
3 years ago
15

What is the answer for this? Please help

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
7 0

Answer:

A or D maybe

Step-by-step explanation:

I don't really know I'm confused myself

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Find the midpoint of AB.<br><br> 1. (4.5, 4.5)<br> 2. (1.5, 1.5)<br> 3. (3, 3)<br> 4. (2, 2)
eimsori [14]

Answer:

2. (1.5, 1.5)

Step-by-step explanation:

midpoint = (x1+x2)/2  , (y1+y2)/2

A = (-3,-3)   and B = (6,6)

midpoint = (-3+6)/2,  (-3+6)/2

              = 3/2 ,  3/2

5 0
3 years ago
1. Let the test statistics Z have a standard normal distribution when H0 is true. Find the p-value for each of the following sit
Nonamiya [84]

Answer:

1 a  p -value  =   0.030054

1b   p -value  =   0.0029798

1c  p -value  = 0.0039768  

2a  p-value  =   0.00099966

2b  p-value  =  0.00999706

2c  p-value   = 0.0654412

Step-by-step explanation:

Considering question a

  The alternative hypothesis is H1:μ>μ0

   The test statistics is  z =1.88

Generally from the z-table  the  probability of   z =1.88 for a right tailed test is

    p -value  =  P(Z > 1.88) = 0.030054

Considering question b

  The alternative hypothesis is H1:μ<μ0

   The test statistics is  z=−2.75

Generally from the z-table  the  probability of   z=−2.75 for a left tailed test is

    p -value  =  P(Z < -2.75) = 0.0029798

Considering question c

  The alternative hypothesis is H1:μ≠μ0

   The test statistics is  z=2.88

Generally from the z-table  the  probability of  z=2.88 for a right  tailed test is

    p -value  = P(Z >2.88) =  0.0019884    

Generally the p-value for the two-tailed test is

    p -value  = 2 *  P(Z >2.88) =  2 * 0.0019884    

=> p -value  = 0.0039768  

Considering question 2a

    The alternative hypothesis is H1:μ>μ0

     The sample size is  n=16

     The  test statistic is  t =  3.733

Generally the degree of freedom is mathematically represented as

        df =  n - 1

=>     df =  16 - 1

=>     df =  15

Generally from the t distribution table  the probability of   t =  3.733 at a degree of freedom of  df =  15 for a right tailed test is  

       p-value  =  t_{3.733 ,  15} = 0.00099966

Considering question 2b

    The alternative hypothesis is H1:μ<μ0

     The degree of freedom is df=23

     The  test statistic is ,t= −2.500

Generally from the t distribution table  the probability of   t= −2.500 at a degree of freedom of  df=23 for a left  tailed test is  

       p-value  =  t_{-2.500 ,  23} = 0.00999706

Considering question 2c

    The alternative hypothesis is H1:μ≠μ0

     The sample size is  n= 7

     The  test statistic is ,t= −2.2500

Generally the degree of freedom is mathematically represented as

        df =  n - 1

=>     df =  7 - 1

=>     df =  6

Generally from the t distribution table  the probability of   t= −2.2500 at a degree of freedom of  df =  6 for a left   tailed test is  

       t_{-2.2500 , 6} = 0.03272060

Generally the p-value  for t= −2.2500 for a two tailed test is

     p-value  =  2 *  0.03272060 = 0.0654412

4 0
3 years ago
Help me solve this problem please
mel-nik [20]
It’s only a vertical angle
7 0
3 years ago
A cylinder and a cone have the same radius and height. How many times greater is the volume of the cylinder than the volume of t
riadik2000 [5.3K]

Answer:

9cm

Step-by-step explanation:

I guessed until I got the right answer

4 0
3 years ago
A triangle can’t be more than one right angle. True or False?
BabaBlast [244]

Answer: True. A triangle is not able to have more than 1 right angle.

Hope this helps.




5 0
3 years ago
Read 2 more answers
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