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2 years ago

Which of the following is the quotient of the rational expressions shown here? x/x-1 / 1/x+1.

Mathematics

1 answer:

grandymaker [24]2 years ago

6 0

Answer:

Assignment: 01.07 Laboratory

: 01.07 Laboratory Techniques

Assignment: 01.07 Laboratory

: 01.07 Laboratory Techniques

Assignment: 01.07 Laboratory

: 01.07 Laboratory Techniques

Assignment: 01.07 Laboratory

: 01.07 Laboratory Techniques

Assignment: 01.07 Laboratory

: 01.07 Laboratory Techniques

Step-by-step explanation:

Assignment: 01.07 Laboratory

: 01.07 Laboratory Techniques

Assignment: 01.07 Laboratory

: 01.07 Laboratory Techniques

Assignment: 01.07 Laboratory

: 01.07 Laboratory Techniques

Assignment: 01.07 Laboratory

: 01.07 Laboratory Techniques

Assignment: 01.07 Laboratory

: 01.07 Laboratory Techniques

Assignment: 01.07 Laboratory

: 01.07 Laboratory Techniques

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Nadine mixes a juice solution that is made from 3 gallons of an 80% juice solution and 1 gallon of a 20% juice solution. What is

motikmotik

Nadine mixes a juice solution that is made from 3 gallons of an 80% juice solution and 1 gallon of a 20% juice solution. What is the percent concentration of the final solution? =65%

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3 years ago

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Solve the equation. 9 = – x + 8

lord [1]

Answer:

x = - 1

Step-by-step explanation:

Given

9 = - x + 8 ( subtract 8 from both sides )

1 = - x ( multiply both sides by - 1 )

- 1 = x ⇒ x = - 1

5 0

3 years ago

(m^-4/3)^1/4 divided by m^0 n^3/4(m^-3/2 n^2)

postnew [5]

$\frac{(m^{-\frac{4}{3}})^{\frac{1}{4}}}{m^{0}(m^{-\frac{3}{2}}n^{2})} = \frac{m^{-\frac{1}{3}}}{m^{-\frac{3}{2}}n^{2}} = \frac{m^{\frac{3}{2}}}{m^{\frac{1}{3}}n^{2}} = \frac{m^{\frac{7}{6}}}{n^{2}} = \frac{\sqrt[6]{m^{7}}}{n^{2}} = \frac{\sqrt[6]{m^{6} * m}}{n^{2}} = \frac{\sqrt[6]{m^{6}}\sqrt[6]{m}}{n^{2}} = \frac{m\sqrt[6]{m}}{n^{2}}$

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3 years ago

Seven less than two times a number is 29.

Alexxx [7]

2x-7=29

"Seven less than" => minus 7.
"Two times a number" => 2x (x is the unknown number)
"is twenty-nine" => =29
Putting it all together,

-7 + 2x = 29
or
2x-7=29
(if you were wondering x is equal to 18)

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3 years ago

What eigen value for this matix (1 -2) (-2 0)

natali 33 [55]

You find the eigenvalues of a matrix A by following these steps:

Compute the matrix $A' = A-\lambda I$ , where I is the identity matrix (1s on the diagonal, 0s elsewhere)
Compute the determinant of A'
Set the determinant of A' equal to zero and solve for lambda.

So, in this case, we have

$A = \left[\begin{array}{cc}1&-2\\-2&0\end{array}\right] \implies A'=\left[\begin{array}{cc}1&-2\\-2&0\end{array}\right]-\left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right]=\left[\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right]$

The determinant of this matrix is

$\left|\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right| = -\lambda(1-\lambda)-(-2)(-2) = \lambda^2-\lambda-4$

Finally, we have

$\lambda^2-\lambda-4=0 \iff \lambda = \dfrac{1\pm\sqrt{17}}{2}$

So, the two eigenvalues are

$\lambda_1 = \dfrac{1+\sqrt{17}}{2},\quad \lambda_2 = \dfrac{1-\sqrt{17}}{2}$

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3 years ago

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