Could someone please help me? If you know all the answers please write down what the answers are. Also, tell me how you got the
answer. Will mark brainlist for the best answer for solving the equations or questions.
2 answers:
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Solution :
Mean time for an automobile to run a 5000 mile check and service = 1.4 hours
Standard deviation = 0.7 hours
Maximum average service time = 1.6 hours for one automobile
The z - score for 1.6 hours =
= 2.02
Now checking a normal curve table the percentage of z score over 2.02 is 0.0217
Therefore the overtime that will have to be worked on only 0.217 or 2.017% of all days.