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Jet001 [13]
3 years ago
9

Hi, will ya'll please help me..?

Mathematics
1 answer:
kirill [66]3 years ago
5 0

Answer:

1. 48

2. 45

3. 32

4. B

Step-by-step explanation: Hope this help :D

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What is the arc measure of BDC in degrees?<br> (4k + 159)<br> P<br> (2k + 153)
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<h2>Explanation:</h2><h2></h2>

The diagram is missing but I'll assume that the arc BDC is:

(4k + 159)^{\circ}

And another arc, let's call it FGH. measures:

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If those arc are equal, then this equation is true:

(4k + 159)^{\circ}=(2k + 153)^{\circ} \\ \\ (4k + 159)=(2k + 153) \\ \\ \\ Solving \ for \ k: \\ \\ 4k-2k=153-159 \\ \\ 2k=-6 \\ \\ k=-\frac{6}{2} \\ \\ k=-3

Substituting k into the first equation:

\angle BDC=(4(-3)+159)^{\circ} \\ \\ \angle BDC=(-12+159)^{\circ} \\ \\ \boxed{\angle BDC=147^{\circ}}

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