A regular trapezoid is shown in the picture attached.
We know that:
DC = minor base = 4
AB = major base = 7
AD = BC = lateral sides or legs = 5
Since the two legs have the same length, the trapezoid is isosceles and we can calculate AH by the formula:
AH = (AB - DC) ÷ 2
= (7 - 5) ÷ 2
= 2 ÷ 2
= 1
Now, we can apply the Pythagorean theorem in order to calculate DH:
DH = √(AD² - AH²)
= √(5² - 1²)
= √(25 - 1)
= √24
= 2√6
Last, we have all the information needed in order to calculate the area by the formula:

A = (7 + 5) × 2√6 ÷ 2
= 12√6
The area of the regular trapezoid is
12√6 square units.
Answer:
Z = 34
Step-by-step explanation:
From the series, we have that:
a = -2
a + d = 7
Hence, -2 + d = 7
∴ d = 7 + 2 = 9
a + 2d = X; a + 3d = Y and a + 4d = Z
-2 + 4(9) = Z
∴ Z = 36 - 2 = 34
The answer is A. Working the formula backwards you get that r^2=256, so r=16
Answer :
F-1(x)=-x/4-7/4
This is right
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