Answer:
Gila Monster is 1.54 times that of Chuckwalla.
Step-by-step explanation:
Given:
Average Length of Gila Monster = 0.608 m
Average Length of Chuckwalla = 0.395 m
We need to find the number of times the Gila monster is as the Chuckwalla.
Solution:
Now we know that;
To find the number of times the Gila monster is as the Chuckwalla we will divide the Average Length of Gila Monster by Average Length of Chuckwalla.
framing in equation form we get;
number of times the Gila monster is as the Chuckwalla = 
Rounding to nearest hundredth's we get;
number of times the Gila monster is as the Chuckwalla = 1.54
Hence Gila Monster is 1.54 times that of Chuckwalla.
Answer:
so basically is right how you write but multiplication goes first
Answer:
a segment is partitioned at a ratio of 1:3, then the point is one-fourth of the distance from (-4,-1) to (2,7).
To compute the x-coordinate of that point, you will need to compute one-fourth of the x-distance between 2 and -4 then add it to -4: (2--4)/4 = 1.5; 1.5 + -4 = -2.5.
To compute the y-coordinate of that point, you will need to compute one-fourth of the y-distance between 7 and -1 then add it to -1: (7--1)/4 = 2; 2 + -1 = 1.
The point is (-2.5,1)
Answer:
(a) 
(b) 
(c) At 4 weeks, when both will be seeing an average of 3 hours of TV.
Step-by-step explanation:
a) For the students, they start at X(0)=5 h and ΔX=-0.5 h/week.
We can write
b) For the professors, they start at X(0)=1 h and ΔX=+0.5 h/week.
We can write
c) The seew which they will be watching the same amount of hours will be the 4th week.
The amount of hours will be
