Answer:

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795
Step-by-step explanation:
Given
See attachment for class
Solving (a): Fill the midpoint of each class.
Midpoint (M) is calculated as:

Where
Lower class interval
Upper class interval
So, we have:
Class 63-65:

Class 66 - 68:

When the computation is completed, the frequency distribution will be:

Solving (b): Mean and standard deviation using 1-VarStats
Using 1-VarStats, the solution is:


<em>See attachment for result of 1-VarStats</em>
The distance rounded to the nearest tenth is 333.7 kilometers
Answer:
13.24
Step-by-step explanation:
If you put it into the calculator, you get the answer. Or you could do long division, but that's difficult for no reason. You could also divide each number individually by 2, as they are all even, so that works too.
Hope this helps!