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Darina [25.2K]
2 years ago
11

Solve for (0,2π] 2cos ß * sin ß = cos ß

Mathematics
1 answer:
Temka [501]2 years ago
4 0

Given :

An equation, 2cos ß sin ß = cos ß .

To Find :

The value for above equation in (0, 2π ] .

Solution :

Now, 2cos ß sin ß = cos ß

2 sin ß = 1

sin ß = 1/2

We know, sin ß = sin (π/6)  or sin ß = sin (5π/6) in  ( 0, 2π ] .

Therefore,

\beta = \dfrac{\pi}{6}\ or\ \beta = \dfrac{5\pi}{6}

Hence, this is the required solution.

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
D is the midpoint of CE. If CD= 2x+10 and DE =3x-18, find x and CE<br><br> x=<br> CE=
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Answer:

<h2>x = 28</h2><h2>CE = 132</h2><h2 />

Step-by-step explanation:

|<------------- CE -------------------->|

C-------------------D-------------------E

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3 years ago
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