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3 years ago

Solve the inequality |* +31 < |2x + 1. |x+3|<|2x+1|

Mathematics

1 answer:

Kisachek [45]3 years ago

7 0

Answer:

Step-by-step explanation:

Here are the steps to follow when solving absolute value inequalities:

Isolate the absolute value expression on the left side of the inequality.

If the number on the other side of the inequality sign is negative, your equation either has no solution or all real numbers as solutions.

If your problem has a greater than sign (your problem now says that an absolute value is greater than a number), then set up an "or" compound inequality that looks like this:

(quantity inside absolute value) < -(number on other side)

(quantity inside absolute value) > (number on other side)

The same setup is used for a ³ sign.

If your absolute value is less than a number, then set up a three-part compound inequality that looks like this:

-(number on other side) < (quantity inside absolute value) < (number on other side)

The same setup is used for a £ sign

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Find the area of the parking space if the height is 18 feet and the base is 9 1/4 feet

Molodets [167]

Area= base x height
So, the base is 9 1/4 and the height is 18 feet
so, the Area= 9 1/4 x 18

9 1/4 x 18
= 166.5

4 0

3 years ago

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Help me please with explanation

8_murik_8 [283]

Step-by-step explanation:

angle AOB = x+3

angle AOC = 2x + 11

angle BOC = 4x-7

angle AOC = angle AOB + angle BOC

=> 2x +11 = (x+3) + (4x-7)

2x +11 = 5x - 4

=> 3x = 15

x = 5

subst x = 5 in the given formulas

angle AOB = x +3 =8

angle AOC = 2x + 11 = 21

angle BOC = 4x - 7 = 13

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3 years ago

Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

Andre45 [30]

Answer:

Option d) 5 to the power of negative 5 over 6 is correct.

$\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

ie, $5^\frac{\bf -5}{\bf 6}$

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

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3 years ago

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Step-by-step explanation:

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2 years ago

Help Please!! Ill Give Brainliest!

vladimir1956 [14]

Question:

On a coordinate grid, point A is located in the first quadrant. Point B is located at (negative 1 over 2, 2).

Point C is a reflection of point B across the y-axis. Which graph shows these three points?

Answer:

What are you telling me? I would help, but can you type in answer choices if there is. That would be very helpful. I don't understand what is " A coordinate grid from negative 3 to positive 3 on both axes is drawn in increments of 1 over 2. Point A is plotted 4 grid lines to the right of the y-axis and 1 grid line above the axis. Point B is plotted at 1 grid line to the left of the y-axis and 4 grid lines above the x-axis. Point C is plotted at 1 grid line to the left of the y-axis and 4 grid lines below the x-axis.

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A coordinate grid from negative 3 to positive 3 on both axes is drawn in increments of 1 over 2. Point A is plotted 2 grid lines to the left of the y-axis and 4 grid lines above the axis. Point B is plotted at 1 grid line to the right of the y-axis and 4 grid lines above the x-axis. Point C is plotted at 1 grid line to the left of the y-axis and 4 grid lines below the x-axis.

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Step-by-step explanation:

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3 years ago

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