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const2013 [10]
3 years ago
8

How many different varieties of pizza can be made if you have the following choice: small, medium, or large size; thin and crisp

y, hand-tossed or pan crust; and 12 toppings (cheese is automatic) from which you may select from 0 to 12?
a) 2 * 3C3
b) 2 * 4C3
c) 2 * 5C3
d) 2 * 6C3
Mathematics
1 answer:
Komok [63]3 years ago
4 0

Answer:

There will be 36,864 different varieties.

Step-by-step explanation:

As given we have following options:

Size: small, medium, or large (3)

Style: thin and crispy, hand-tossed, or pan crust (3)

Toppings: 12 choices

Lets say the order of toppings does not matter.

So, number of ways of topping = 2^{12}

Hence, total number of different pizzas will be :

3\times3\times2^{12}

= 36864 different varieties.

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Fantom [35]

Answer:

A. the equality means that the two equations should be equal in a certain x value. Solving the x for these equation gives you the x point where the 2 equations intersect.

B. The x value where the funcionts intersect is x = 1

Step-by-step explanation:

You can solve the x value using natural logarithms.

If you make a table for the two functions you will also see the result:

Value             y = 8^x            y = 2^(x+2)

 -3                    0,00195          0,5

 -2                    0,0156             1

 -1                     0,125               2

  0                     1                      4

  1                      8                     8

  2                      64                  16

  3                      512                  32

8 0
3 years ago
How do I solve this problem, or can I have an answer to this problem?
azamat
Well first you have to know what i is. i is the sqrt of -1 so try doing 3+5(sqrt-1)/1+sqrt-1. I don't know how to solve it though sorry
7 0
3 years ago
Find the value of x. Then find the missing angle measures of the polygon.
Naily [24]

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