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3 years ago

For geometry:( will give brainist to the correct answer!!!

Mathematics

1 answer:

Strike441 [17]3 years ago

5 0

Answer:

y = ⅔x - 5

Step-by-step explanation:

To write the equation, find the slope (m), to enable you write the equation of the line in point-slope form given a point, (-3, -7) that the line passes through.

Since the line is parallel to 2x - 3y = 24,, it would have the same slope (m) value.

Rewrite 2x - 3y = 24 in slope-intercept form.

Thus:

2x - 3y = 24

-3y = -2x + 24

y = ⅔x - 12

The slope of 2x - 3y = 24 is ⅔. Therefore, the line that is parallel to 2x - 3y = 24 is also ⅔.

To write the equation of the line, substitute (a, b) = (-3, -7) and m = ⅔ into y - b = m(x - a)

Thus:

y - (-7) = ⅔(x - (-3))

y + 7 = ⅔(x + 3)

y + 7 = ⅔x + 2

y = ⅔x + 2 - 7

y = ⅔x - 5

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How many solutions does the equation 3n + 5 (n-4) = 9n -5 have

Tju [1.3M]

$3n + 5(n - 4) = 9n - 5 \\ \\ 3n + 5n - 20 = 9n - 5 \\ \\ 8n - 20 = 9n - 5 \\ \\ 8n - 9n = - 5 + 20 \\ \\ - n = 15 \\ \\ n = - 15$

<h3>Hope This Helps</h3>

8 0

2 years ago

Which expression is equivalent to -18a^-2b^5/-12a^-4b^-6

crimeas [40]

Answer:

c. 3a^2b^11/2

Step-by-step explanation:

The applicable rule of exponents is ...

(a^b)/(a^c) = a^(b-c)

$\dfrac{-18a^{-2}b^5}{-12a^{-4}b^{-6}}=\dfrac{-18}{-12}a^{-2-(-4)}b^{5-(-6)}=\boxed{\dfrac{3a^2b^{11}}{2}}$

3 0

2 years ago

Oneta writes an algebraic expression with three terms. The y-term has a coefficient of -3, and the x-term has a coefficient of 1

Rina8888 [55]

X - 3y + z

Another term would be the 3rd term which would be working with 3d planes instead of 2d planes.

3 0

3 years ago

Read 2 more answers

(6,5) what is b y=mx+b

PolarNik [594]

Answer:

b = y-intercept

Step-by-step explanation:

7 0

2 years ago

Can u guys PLEASE ANSWER this question ASAP.

qwelly [4]

Answer:

x = -14

Step-by-step explanation:

The expression to write in this problem is:

"the sum of x and 12 equals the sum of half of x and 5"

We have:

- The sum of x and 12 is: $x+12$

- The sum of half of x and 5 is: $\frac{1}{2}x+5$

So, the equation to write in this problem is

$x+12=\frac{1}{2}x+5$

We solve it as follows:

1) First, we subtract $\frac{1}{2}x$ from both sides, and we get

$x-\frac{1}{2}x+12=\frac{1}{2}x-\frac{1}{2}x+5\\\frac{1}{2}x+12=5$

2) Then, we subtract 12 from both sides:

$\frac{1}{2}x+12-12=5-12\\\frac{1}{2}x=-7$

3) Now we multiply both sides by 2:

$\frac{1}{2}x\cdot 2=-7\cdot 2\\x=-14$

So, this is the solution.

8 0

3 years ago