Answer:
Eight thousand fourteen hundred twelve and seven
Given:
Angled formed by ray BA and ray BC is 90 degrees.
To find:
The equation of line that bisects the angle formed by ray BA and ray BC.
Solution:
If a line bisects the angle formed by ray BA and ray BC, then it must be passes through point B and makes angles of 45 degrees with ray BA and ray BC.
It is possible if the line passes though point B(-1,3) and other point (-2,4).
Equation of line is
Add 3 on both sides.
Therefore, the required equation of line is .
Step-by-step explanation:
First;
x to third power=x³
y to 4th power=y⁴
<u>A</u><u>c</u><u>c</u><u>o</u><u>r</u><u>d</u><u>i</u><u>n</u><u>g</u><u> </u><u>t</u><u>o</u><u> </u><u>c</u><u>o</u><u>n</u><u>d</u><u>i</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u>
expression=x³ × y⁴
=x³y⁴
Answer:
The period of the sine curve is the length of one cycle of the curve. The natural period of the sine curve is 2π. So, a coefficient of b=1 is equivalent to a period of 2π. To get the period of the sine curve for any coefficient b, just divide 2π by the coefficient b to get the new period of the curve.
Step-by-step explanation:
62° is the answer. Just add 26 and 36.
