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Arada [10]
3 years ago
15

Will give Branliest.Thanks, :)​

Mathematics
1 answer:
Darina [25.2K]3 years ago
3 0

Answer:

1) m=7

2) y=8

3)m=9

4) a=121

5) t=30

6)h=7

Noah's number is 15

S=15

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Please help me on this >_
Morgarella [4.7K]

Answer: x=74°

180-133=47 and 47+59=106 so 180-106= 74°

5 0
3 years ago
Read 2 more answers
Two ice cream stands are deciding where to set up along a 1-mile-long beach. The people are uniformly located along the beach, a
larisa [96]

Answer:

Each ice cream seller wants the maximum number of customers:

True

The two ice cream stands will most likely be 1/3 mile away from each other.

True

Step-by-step explanation:

This distance enables the two ice cream stands to give access to the maximum number of customers at the beach, which will be almost equal at their right-hand and left-hand sides.  Therefore, the two ice cream stands will most likely be 1/3 mile away from each other.  Such positioning exposes the ice cream stands to almost equal number of customers since the people standing along the beach are uniformly located.  Taking the extreme locations along the 1-mile-long beach will shrink location opportunities for both stands.

7 0
3 years ago
4•6÷2 to the power of 3=
makvit [3.9K]

The answer is 1728

First you must set up the equation

(\frac{4*6}{2})^3

Then, you must multiply the numerator

(\frac{24}{2} )^3

Next, divide

(12)^3

Finally, simplify exponents

(12^3) =12*12*12

12*12*12=1728

4 0
4 years ago
Read 2 more answers
Helpp...!!! Ppease i need helpppp
guajiro [1.7K]

Answer:

c

Step-by-step explanation:

3 0
3 years ago
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Solve ( x + 1 < 5) ∩ ( x - 4 > -3).
mina [271]

Answer:

<em>The answer is: { all those real numbers x | 1<x<4}</em>

Step-by-step explanation:

We have to find the common region for the inequalities:

x+1<5 and x-4>-3  ; where x is a real number.

i.e we need to find the region of  ( x + 1 < 5) ∩ ( x - 4 > -3).

let us find the region for : x+1<5    

              ⇒        x<5-1    (subtracting both side by 1)

              ⇒        x<4

the region is (-∞,4)

in set-builder definition form it could be written as: { all those real number x | -∞<x<4}

now calculating the region for the second inequality:  x-4>-3

     ⇒   x>-3+4     (Adding 4 on both the sides of the inequality)

    ⇒   x>1

Hence, the region is   (1,∞)

in set-builder definition form it could be written as: { all those real number x | 1<x<∞}.

So, the common region in (-∞,4) and (1,∞) i.e. (-∞,4)∩(1,∞)=(1,4).

Hence the answer is: { all those real numbers x | 1<x<4}.

         


4 0
4 years ago
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