3 years ago

Help! I can’t figure this out!

Mathematics

1 answer:

Rama09 [41]3 years ago

5 0

The image is blurry what’s the question?

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MN bisects OP at point Q . Which statement is true OQ=QP MQ=QN MQ=QP OQ=QN

barxatty [35]

OQ is equal to QP so the first option is correct

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3 years ago

Find equation of vertical line through (-5, -3)

Novay_Z [31]

Answer:

x = -5

Step-by-step explanation:

Given that it is a vertical line, we know that it will only go through one x-value.

We are also given a point, (-5, -3).

This point tells us that the vertical line only goes through the x-value -5, so the equation will be x = -5.

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4 years ago

There are 5 students enrolled in Ms. Rodriguez's class. There are 6 students absent and 18 students present today. Write an equa

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5-6+18 is the answer

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3 years ago

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Simplify the expression. 5 + 18 divided 3x2

mestny [16]

Answer:

3.83333333333

Step-by-step explanation:

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3 years ago

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Find dy/dx when y = Ln (sinh 2x). A. 2 cosh 2x B. 2 sech 2x C. 2 coth 2x D. 2 csch 2x

givi [52]

The function given is a composite function. Let's work from the outside in:
$y=(ln(sinh(2x)))$

First step:
$\frac{d}{dx}[y]= \frac{d}{dx}[ln(sinh(2x))]$

Now, let's work it out:
$\frac{dy}{dx} = \frac{1}{sinh(2x) } * \frac{d}{dx}[sinh(2x)]$

Next step:
$\frac{dy}{dx} = \frac{1}{sinh(2x) } * cosh(2x) * \frac{d}{dx}[2x]$

Next step:
$\frac{dy}{dx} = \frac{1}{sinh(2x) } * cosh(2x) *2$

Simplify:
$\frac{dy}{dx} = \frac{2cosh(2x)}{sinh(2x) }$

Simplify further:
$\frac{dy}{dx} = 2 (\frac{cosh(2x)}{sinh(2x)})$

Remember that:
${\frac{cosh(x)}{sinh(x)} = coth(x)$

So, your final answer is:
$\boxed{ \frac{dy}{dx} = 2coth(2x) }$

So, your answer is C. Hope I could help you!

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4 years ago