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irina [24]
3 years ago
7

Find dy/dx when y = Ln (sinh 2x). A. 2 cosh 2x B. 2 sech 2x C. 2 coth 2x D. 2 csch 2x

Mathematics
1 answer:
givi [52]3 years ago
8 0
The function given is a composite function. Let's work from the outside in:
y=(ln(sinh(2x)))

First step:
\frac{d}{dx}[y]= \frac{d}{dx}[ln(sinh(2x))]

Now, let's work it out:
\frac{dy}{dx} = \frac{1}{sinh(2x) } *   \frac{d}{dx}[sinh(2x)]

Next step:
\frac{dy}{dx} = \frac{1}{sinh(2x) } * cosh(2x) *  \frac{d}{dx}[2x]

Next step:
\frac{dy}{dx} = \frac{1}{sinh(2x) } * cosh(2x) *2

Simplify:
\frac{dy}{dx} = \frac{2cosh(2x)}{sinh(2x) }

Simplify further:
\frac{dy}{dx} = 2 (\frac{cosh(2x)}{sinh(2x)})

Remember that:
{\frac{cosh(x)}{sinh(x)} = coth(x)

So, your final answer is:
\boxed{ \frac{dy}{dx} = 2coth(2x) }

So, your answer is C. Hope I could help you!
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