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vichka [17]
3 years ago
14

There are between 24 and 40 students in a class.

Mathematics
1 answer:
nexus9112 [7]3 years ago
7 0
There are 12 boys and 21 girls for a total of 33 students
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What 5 numbers that round down to 600
8090 [49]
*It depends what place value needs to be rounded down, but without any specific place values, here are my answers*

<em>600.1</em>

<em>601</em>

<em>600.44</em>

<em>602.1</em>

<em>644.4</em>
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

-Hope this helps :)


6 0
4 years ago
Solve for t if p≠q<br> (t+p)/q - q/p = (t-q)/p + p/q
german

Answer:

.. q T 0 = (q/p)a (q/p)a − (q/p)T−10 if p ≠ q and qT0 = 1 − T0/a if p = q = 1/2.

Step-by-step explanation:

Suppose that there are two different solutions, p and q, in [a, b]. Thus p =g(p) q =g(q) p ≠ q The function g(x) satisfies the hypotheses of the mean-value ... that g(p) –g(q) = (p – q) g׳(t) Because g(p) =p and g(q) = q, the left side of Eq. (1-3) may...

6 0
3 years ago
What will be the answer if we multiply a+b by ab
VARVARA [1.3K]

Step-by-step explanation:

(a+b)(ab)

{a}^{2} b + a  {b}^{2}

6 0
3 years ago
Integration of ∫(cos3x+3sinx)dx ​
Murljashka [212]

Answer:

\boxed{\pink{\tt I =  \dfrac{1}{3}sin(3x)  - 3cos(x) + C}}

Step-by-step explanation:

We need to integrate the given expression. Let I be the answer .

\implies\displaystyle\sf I = \int (cos(3x) + 3sin(x) )dx \\\\\implies\displaystyle I = \int cos(3x) + \int sin(x)\  dx

  • Let u = 3x , then du = 3dx . Henceforth 1/3 du = dx .
  • Now , Rewrite using du and u .

\implies\displaystyle\sf I = \int cos\ u \dfrac{1}{3}du + \int 3sin \ x \ dx \\\\\implies\displaystyle \sf I = \int \dfrac{cos\ u}{3} du + \int 3sin\ x \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}\int \dfrac{cos(u)}{3} + \int 3sin(x) dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3} sin(u) + C +\int 3sin(x) dx \\\\\implies\displaystyle \sf I = \dfrac{1}{3}sin(u) + C + 3\int sin(x) \ dx \\\\\implies\displaystyle\sf I =  \dfrac{1}{3}sin(u) + C + 3(-cos(x)+C) \\\\\implies \underset{\blue{\sf Required\ Answer }}{\underbrace{\boxed{\boxed{\displaystyle\red{\sf I =  \dfrac{1}{3}sin(3x)  - 3cos(x) + C }}}}}

6 0
3 years ago
Solve -5y+6=-9 pls help me with this
alexandr402 [8]

Answer:

-5y + 6 = -9

y = 3

Step-by-step explanation:

subtract 6 from both sides

-5y + 6 - 6 = -9 - 6

simplify

-5y = -15

divide both sides by -5

(-5y)/5 = (-15)/5

simplify

y = 3

6 0
3 years ago
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