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butalik [34]
3 years ago
6

From the list below, determine which properties are for compounds. I. It takes a large amount of energy to separates the element

s of a compound. II. The proportions of the elements in a compound are always fixed. III. It is easy to separate the elements of a compound. IV. The elements/components of a compound do not retain their individual properties. A) I & II B) II & III C) I, II & IV D) II, III, & IV
Mathematics
2 answers:
klasskru [66]3 years ago
3 0

 1 , 2 & 4 are all properties of compounds.

 The answer would be C

Bingel [31]3 years ago
3 0
The correct answer is C <span>a mixture that is uniform in composition, </span>components<span> are evenly distributed and </span>not easily<span> distinguished ... They </span>can<span> have some same extensive </span>properties<span> if </span>there<span> is the same </span>amount<span> of the samples but they are different </span>elements<span> so the intensive </span>properties<span> are ... What type of </span>properties can<span> be used to </span>separate <span>mixtures? That is the answer hope I helped God bless you and your family Have a Merry Christmas #Remember pray and tell God Happy birthday your in my prayers</span>
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No she not correct. 80% of the students are wearing tennis shoes
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Part 1. Please show work. Please assist me with these math problems. ​
Vitek1552 [10]

Answer: 1) 2, 3, 4, 9, 32, 279, 8896, 2481705, 22077238784

              2) 2,490,924

              3) Neither

<u>Step-by-step explanation:</u>

S_n=S_{n-2}\cdot (S_{n-1}-1)\quad \\\\S_1=2\quad given\\S_2=3\quad given\\S_3=S_1(S_2-1)\quad =2(3-1)\quad =4\\S_4=S_2(S_3-1)\quad =3(4-1)\quad =9\\S_5=S_3(S_4-1)\quad =4(9-1)\quad =32\\S_6=S_4(S_5-1)\quad =9(32-1)\quad =279\\S_7=S_5(S_6-1)\quad =32(279-1)\quad =8,896\\S_8=S_6(S_7-1)\quad =279(8896-1)\quad =2,481,705\\S_9=S_7(S_8-1)\quad =8896(2481705-1)\quad =22,077,238,784

\sum^8_{k=1}S_k\\\\=S_1+S_2+S_3+S_4+S_5+S_6+S_7+S_8\\\\= 2,490,924\\

Neither

Not arithmetic because the difference between each of the terms is not the same.            

                        S₂ - S₁          S₃ - S₂           S₄ - S₃      

                      3 - 2 = 1       4 - 3 = 1          9 - 4 = 5

Not geometric because the ratios between each of the terms is not the same.                

                       \dfrac{S_2}{S_1}=\dfrac{S_3}{S_2}\qquad \rightarrow \dfrac{3}{2}=\dfrac{4}{3}\qquad \rightarrow \text{cross multiply to get}: 9\neq 8

8 0
3 years ago
How does the graph of the function g(x) = 2x - 3 differ from the graph of f(x) = 2X?
fredd [130]

Answer:

A

Step-by-step explanation:

Ο Α.

A. It is moved up 3 units.

4 0
2 years ago
Point A is located at (−2, −6), and D is located at (−6, 8). Find the coordinates of the point that lies halfway between A and D
Afina-wow [57]

Answer:

(-4,1)

Step-by-step explanation:

Point A is located at (−2, −6), and D is located at (−6, 8).

We need to find the midpoint of A  and D

Mid point formula is (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

Point A is (-2,-6) that is (x1,y1)

Point D is (-6,8) that is (x2, y2)

plug in the values in the formula

(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

(\frac{-2-6}{2}, \frac{-6+8}{2})

(\frac{-8}{2}, \frac{2}{2})

Mid point is (-4, 1)

5 0
3 years ago
Read 2 more answers
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