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2 years ago

X=2t/t^2 +1 and y=2t/t^2 +1 Find dy/dx

Mathematics

1 answer:

zhenek [66]2 years ago

7 0

Answer:

dy/dx=1

Hope this helps! Please vote brainliest! :)

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vaieri [72.5K]

Answer:

its 136

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2 years ago

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Given that the first step of the sequence of transformations that maps ABCD to PQRST is a reflection, identify the the transform

olga55 [171]

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2 years ago

Can someone help please?

Katarina [22]

Answer:

g = 6

Step-by-step explanation:

<em>To find the slope you do:</em>

m = change in y ÷ change in x or (y2 - y1) ÷ (x2 - x1)

x1 = 4, y1 = -7
x2 = g, y2 = -3
m (the slope) = 2

<em>Sub in the values:</em>

2 = (-3 - -7) ÷ (g - 4) - we can simplify this

2 = (4) ÷ (g - 4)

4 divided by what gives us 2? 2. This means that g - 4 = 2, g = 2 + 4 which is 6:

g = 6

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3 years ago

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Which of the ordered pairs in the form (x, y) is a solution of this equation?

Tju [1.3M]

Answer:

Both ordered pairs are solutions to this equation.

Step-by-step explanation:

If you plug in the x and y values given in the ordered pair, you make the left side of the equation equal the right for both pairs.

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3 years ago

The comprehensive strength of concrete is normally distributed with μ = 2500 psi and σ = 50 psi. Find the probability that a ran

VARVARA [1.3K]

Answer:

The probability that the diameter falls in the interval from 2499 psi to 2510 psi is 0.00798.

Step-by-step explanation:

Let's define the random variable, $X =$ "Comprehensive strength of concrete". We have information that $X$ is normally distributed with a mean of 2500 psi and a standard deviation of 50 psi (or a variance of 2500 psi). In other words, $X \sim N(2500, 2500)$ .

We want to know the probability of the mean of X or $\bar{X}$ that falls in the interval $[2499;2510]$ . From inference theory we know that :

$\bar{X} \sim N(2500, \frac{2500}{5}) \Rightarrow \bar{X} \sim N(2500,500)$

Now we can find the probability as follows:

$P(2499 \leq \bar{X} \leq 2510) \Rightarrow P(\frac{2499 - 2500}{500} \leq \frac{\bar{X} - 2500}{500} \leq \frac{2499 - 2500}{500} ) \Rightarrow\\\Rightarrow P(-0.002 \leq \frac{\bar{X} - 2500}{500} \leq 0.02 ) \Rightarrow P(-0.002 \leq Z \leq 0.02 )$

Where $Z \sim N(0,1)$ , then:

$P(-0.002 \leq Z \leq 0.02 ) \approx P(0 \leq Z \leq 0.02 ) = P(Z \leq 0.02 ) - P(Z \leq 0) \\P(0 \leq Z \leq 0.02 ) = 0.50798 - 0.5 = 0.00798$

8 0

3 years ago

X=2t/t^2 +1 and y=2t/t^2 +1 Find dy/dx​

X=2t/t^2 +1 and y=2t/t^2 +1 Find dy/dx