Answer:
- Let p be the population at t be the number of years since 2011. Then,

- The projected population of the high school in 2015=1800
- In <u>2019</u> the population be 1600 students
Step-by-step explanation:
Given: The population at Bishop High School students in 2011 =2000
Also, Every year the population decreases by 50 students which implies the rate of decrease in population is constant.
So, the function is a linear function.
Let p be the population at t be the number of years since 2011.
Then, 
So at t=0, p=2000
In year 2015, t=4, substitute t=4 in the above equation ,we get

Hence, the projected population of the high school in 2015=1800
Now, put p=1600 in the function , we get

Now, 2011+8=2019
Hence, in <u>2019</u> the population be 1600 students
Answer: first part is 2 then 0, after, its “are two real solutions” on edg, yw
Step-by-step explanation:
Hi there
The formula is
A=p (1+r/k)^kt
A future value 3000
P present value 100
R interest rate 0.02
K compounded monthly 12
T time?
We need to solve for t
T=[log (A/p)÷log (1+r/k)]÷k
T=(log(3,000÷100)÷log(1+0.02÷12))÷12
T=170.202 years
So it's a
Hope it helps
5x10^9
Just find out how many zeros there are
Your sloe would be 2/3x because that fraction is rise over run so you go up two and over three positive the -3 is your intercept but he fraction simplified is your slope good luck