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MAXImum [283]
4 years ago
5

Enrique takes out a student loan to pay for his college tuition this year.find the interest o the loan if he borrowed 2,500 at a

n annual interest rate of 6% for 15 years
Mathematics
2 answers:
Ronch [10]4 years ago
6 0
Suppose the interest model payment follows a simple interest model. The amount of interest to be paid will be given by:I=(PRT)/100P=principle=$2500R=rate=6%T=time=15 years.
Therefore:S.I=(2500×6×15)/100=$2250

vampirchik [111]4 years ago
6 0
At simple interest rate:
1 year = 6% of 2500 = 0.06 x 2500 = 150
15 years = 150 x 15 = $2250

At compounded interest rate:
2500(1 + 0,06)^15 - 2500 = $3491.40
You might be interested in
Joseph wants to estimate 1 3/7 . 5 4/5 To estimate, he simplifies the expression 1 1/2 . 6 Is Joseph’s estimate an underestimate
Zolol [24]


Well if her simplifies 1 3/7 to 1 1/2 and 5 4/5 to 6 then he would be overestimating because 1 1/2 is greater than 1 3/7 and 6 is greater than 5 4/5

Hope this helps!

7 0
3 years ago
i promise i will mark brainliest if the point (-3,4) is the vertex point of the curve of aquadratic function f and -5 is aroot o
Jet001 [13]

Ans:

(x+5)(x+1)+8

Step by step explanation:

-5 was mentioned as the 0 of the first root: (x+5). Then with some maneuvering we can plot (-3,4) then add (x+1) because they land on the same y axis. then we add 8 to get it right on the vertex.

6 0
4 years ago
Put these fractions least to greatest 2/3 1/4 5/6 7/10 1/6
givi [52]

Answer:

1/6, 1/4, 2/3, 7/10, 5/6

I hope this helps!

4 0
3 years ago
Change 5x+1=4y+7 to slope intercept form ( y=mx+b)
SSSSS [86.1K]

Answer:

Step-by-step explanation:

5x + 1 = 4y + 7

5x - 4y = 7 - 1

-4y = -5x + 6

-4y/-4 = -5x/-4 + 6/-4

y = 5/4x - 6/4

y = 5/4x - 3/2

7 0
3 years ago
Read 2 more answers
A runner maintains constant acceleration after starting from rest as she runs a distance of 60.0 m. The runner's speed at the en
Svet_ta [14]

Answer:\frac{40}{3}s

Step-by-step explanation:

This is a typical problem of u.a.r.m. ( uniformly accelerated rectilinear motion). Let's take an eye on the u.a.r.m. equations:

v(t) = v_{0} + a.t\\x(t) = x_{0} + v_{0}.t + \frac{1}{2}.a.t^{2}

We know the runner started from rest so we can discard v_{0} as v_{0} = 0

Also we can consider she starts at x_{0} = 0.

All we have to do now is replace these values at our equations to obtain:

v(t) = a.t\\x(t) = \frac{1}{2}.a.t^{2}

As we are told that the acceleration remains constant, we can then find the time it took for her to run the whole distance as follows:

First we note that the ratio between her velocity and the time it takes for her to run a certain distance is constant. This is:

\frac{v(t)}{t} = a ; \forall t

In particular, if we take t=t_{f} where t_{f} is the total time it takes for her to run the whole distance x(t=t_{f})=60m

We know that at this point the velocity is:

v(t=t_{f}) = 9\frac{m}{s}

So that:

a = \frac{v(t=t_{f})}{t_{f}} = \frac{9\frac{m}{s}}{t_{f}}

Now we can replace this in the equation of motion x(t)

x(t=t_{f}) = \frac{1}{2}.a.t^{2} = \frac{1}{2}.\frac{9\frac{m}{s}}{t_{f}}.t_{f}^{2} = 60m

Where we finally find that

t_{f} = \frac{40}{3}s

3 0
3 years ago
Read 2 more answers
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