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matrenka [14]
3 years ago
7

Identify a possible first step using the elimination method to solve the system and then find the solution to the system. 3x - 5

y = -2 & 2x + y = 3
A) Multiply first equation by -3 and second equation by 2, solution (1, 1).
B) Multiply first equation by -2 and second equation by 3, solution (1, 1).
C) Multiply first equation by -3 and second equation by 2, solution (1, -1).
D) Multiply first equation by -2 and second equation by 3, solution (1, -1).
Mathematics
2 answers:
Nastasia [14]3 years ago
7 0

Answer:

see explanation

Step-by-step explanation:

Given the 2 equations

3x - 5y = - 2 → (1)

2x + y = 3 → (2)

Multiply (2) by 5 will eliminate y when added to (1), that is

10x + 5y = 15 → (3)

Add (1) and (3) term by term

(3x + 10x) + (- 5y + 5y) = (- 2 + 15)

13x = 13 ( divide both sides by 13 )

x = 1

Substitute x = 1 into (2) for corresponding value of y

2 + y = 3 ⇒ y = 3 - 2 = 1

Solution is (1, 1)

qaws [65]3 years ago
3 0

Answer:Its B

Step-by-step explanation:

You multiply 2 first and then 3.

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5. Mis the midpoint of CD. C has coordinates (-1,-1) and
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Answer/Step-by-step Explanation:

4. Midpoint (M) of AB, for A(-2, -3) and B(1, 2) is given as:

M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})

Let A(-2, -3) = (x_1, y_1)

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Thus:

M(\frac{-2 + 1}{2}, \frac{-3 + 2}{2})

M(\frac{-1}{2}, \frac{-1}{2})

5. Given M(3, 5) as midpoint of CD, and C(-1, -1),

let C(-1, -1) = (x_2, y_2)

D(?, ?) = (x_1, y_1)

M(3, 5) = (\frac{x_1 +(-1)}{2}, \frac{y_1 +(-1)}{2})

Rewrite the equation to find the coordinates of D

3 = \frac{x_1 - 1}{2} and 5 = \frac{y_1 - 1}{2}

Solve for each:

3 = \frac{x_1 - 1}{2}

3*2 = \frac{x_1 - 1}{2}*2

6 = x_1 - 1

6 + 1= x_1 - 1 + 1

7 = x_1

x_1 = 7

5 = \frac{y_1 - 1}{2}

5*2 = \frac{y_1 - 1}{2}*2

10 = y_1 - 1

10 + 1= y_1 - 1 + 1

11 = y_1

y_1 = 11

Coordinates of D is (7, 11)

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3 years ago
What is the variable of 6(x+5)= -36
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6 (x + 5) = -36

6x +30 = -36 (distribute)

6x +30 (-30) = -36 -30

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x = -11

3 0
4 years ago
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