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3 years ago

What is the solution to -5 (-2 - 3k) = -65

Mathematics

1 answer:

kogti [31]3 years ago

8 0

Answer:

answer= ( = − 5) only k= -5

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Find the midpoint of CD <br> C = (10,-1) and D = (-6,3)

MrRa [10]

Answer: (4/2, 2/2)

Step-by-step explanation:

so the formula is (x1 +x2 divided by 2, y1 + y2 divided by 2)

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3 years ago

LAST ONE! PLEASE HELP! WILL MARK BRAINLIEST!

garri49 [273]

Answer:

Part A) the direct variation equation that relates x and y is:

$y= -5x$

Part B) value of y = 75

Step-by-step explanation:

Part A)

We are given that y varies directly with x, and y=10 when x=-2 what direct variation equation relates x and y?

If x and y are directly related then:

y ∝ x or y=kx

where k is constant of proportionality.

Now, finding k:

y=10 and x=-2

$y=k\,\,x\\10=k*-2\\k=10/-2\\k=-5$

So, value of k = -5

So, the direct variation equation that relates x and y is:

$y= -5x$

Part B)

What is the value of y when x = -15

the equation is:

$y= -5x$

Putting x = -15

$y=-5x\\y=-5(-15)\\y=75$

So, value of y = 75

Keywords: Direct Variation

Learn more about Direct Variation at:

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3 years ago

CAN YOU ANSWER PLS MAKE SURE U R SURE OF UR ANSWER AND HERE IS A INSPIRING QUOTE FOR ALL OF YOU TO NEVER GIVE UP ON LIFE BECAUSE

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* 14 * x=2 * 28 . What x equal ?

AlladinOne [14]

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Step-by-step explanation:

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Prove that an integer consisting of 3n ones is divisible by 3n (e.g. 111 is divisible by 3, 111,111,111 is divisible by 9, etc.)

mote1985 [20]

For proof of 3 divisibility, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.

<h3>Integers divisible by 3</h3>

The proof for divisibility of 3 implies that an integer is divisible by 3 if the sum of the digits is a multiple of 3.

<h3>Proof for the divisibility</h3>

111 = 1 + 1 + 1 = 3 (the sum is multiple of 3 = 3 x 1) (111/3 = 37)

222 = 2 + 2 + 2 = 6 (the sum is multiple of 3 = 3 x 2) (222/3 = 74)

213 = 2 + 1 + 3 = 6 ( (the sum is multiple of 3 = 3 x 2) (213/3 = 71)

27 = 2 + 7 = 9 (the sum is multiple of 3 = 3 x 3) (27/3 = 9)

Thus, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.

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