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2 years ago

What is the approximate percent decrease from 1,865 to 1,240?

Mathematics

2 answers:

Trava [24]2 years ago

4 0

Answer:

33.5

1865 - 625 = 1240

625/1865 = 33.5%

Zanzabum2 years ago

3 0

Answer:

50.4% decrease

Step-by-step explanation:

(difference of two values/original value ) x 100

= (625/1240) x 100

= .504 x 100

= 50.4%

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5/7 = x/70 solve the proportion

irga5000 [103]

5/7 = x/70
multiply both sides by 70
350/7 = x
simplify
50 = x

4 0

2 years ago

Read 2 more answers

the name Joe is very common at a school in one out of every ten students go by the name. If there are 15 students in one class,

kumpel [21]

Using the binomial distribution, it is found that there is a 0.7941 = 79.41% probability that at least one of them is named Joe.

For each student, there are only two possible outcomes, either they are named Joe, or they are not. The probability of a student being named Joe is independent of any other student, hence, the <em>binomial distribution</em> is used to solve this question.

<h3>Binomial probability distribution </h3>

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

One in ten students are named Joe, hence $p = \frac{1}{10} = 0.1$ .

There are 15 students in the class, hence $n = 15$ .

The probability that at least one of them is named Joe is:

$P(X \geq 1) = 1 - P(X = 0)$

In which:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{15,0}.(0.1)^{0}.(0.9)^{15} = 0.2059$

Then:

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.2059 = 0.7941$

0.7941 = 79.41% probability that at least one of them is named Joe.

To learn more about the binomial distribution, you can take a look at brainly.com/question/24863377

8 0

2 years ago

Write the equation of the line with x-intercept -2 and y-intercept -1 in slope-intercept form

eduard

The x-intercept of -2 gives us an idea that point (-2,0) if found along the line. The y-intercept of -1, tells us that point (0,-1), this also tells us that b = -1.

Now that we have two points, we can solve for slope m

$\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ \text{Given two points} \\ (-2,0)\rightarrow(x_1,y_1) \\ (0,-1)\rightarrow(x_2,y_2) \\ \\ \text{Substitute} \\ m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{-1-0}{0-(-2)} \\ m=-\frac{1}{2} \end{gathered}$

Now that we have both m and b. Substitute these values to the slope intercept form

$\begin{gathered} \text{Slope intercept form is} \\ y=mx+b \\ \text{where} \\ m\text{ is the slope} \\ b\text{ is the y-intercept} \\ \\ \text{Substitute the values from before and we get} \\ y=-\frac{1}{2}x-1 \end{gathered}$

5 0

10 months ago

Find the time, amount = Rs 1375, principal =Rs 1250, Rate - 4%

TiliK225 [7]

Answer:

so time is 2 years and 6 months