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LuckyWell [14K]
3 years ago
5

If f(x) = 4x - 8, what is the value of f(-3)?

Mathematics
1 answer:
adoni [48]3 years ago
6 0

Answer:

-20

Step-by-step explanation:

f(x)= 4x-8 f(-3)

y= 4(-3) -8

y= -12 -8

y= -20

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When h(1)=-2, and h(n)=h*(n-1)+n, what is h(2)=
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h(2)=0

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Which of there polynomials could have (x-2) as a factor?
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Answer:

x-2 is a factor of following polynomials:

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Step-by-step explanation:

In order to check that which polynomials might have x-2 as a factor, we will put

x-2 = 0 => x = 2 in each polynomial, if the value of polynomial on 2 is zero then x-2 is a factor otherwise not.

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a(x) = 6x² - 7x - 5

Putting x = 2

a(2) = 6(2)^2-7(2)-5\\= 6(4)-14-5\\=24-14-5\\=24-19\\=5 \neq 0

b(x) = 3x² + 15x - 42

b(2) = 3(2)^2 + 15(2) - 42\\=3(4)+30-42\\=12+30-42\\=42-42 = 0

c(x) = 2x³ + 13x² + 16x + 5

c(2) = 2(2)^3 + 13(2)^2 + 16(2) + 5\\=2(8)+13(4)+32+5\\=16+52+32+5\\=105 \neq 0

d(x) = 3x³ - 2x² - 15x + 14

d(2) = 3(2)^3 - 2(2)^2 - 15(2) + 14\\= 3(8)-2(4)-30+14\\=24-8-30+14\\=38-38 = 0

e(x) = 8x⁴ - 41x³ - 18x² + 101x + 70

e(2) = 8(2)^4 - 41(2)^3 - 18(2)^2 + 101(2) + 70\\= 8(16)-41(8)-18(4)+202+70\\=128-328-72+202+70\\=0

f(2) = (2)^4 + 5(2)^3 - 27(2)^2 - 101(2) - 70\\=16+5(8)-27(4)-202-70\\=16+40-108-202-70\\=-324 \neq 0

Hence,

x-2 is a factor of following polynomials:

  • b(x) = 3x² + 15x - 42
  • d(x) = 3x³ - 2x² - 15x + 14
  • e(x) = 8x⁴ - 41x³ - 18x² + 101x + 70
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