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docker41 [41]
3 years ago
15

How to do the problem

Mathematics
1 answer:
gavmur [86]3 years ago
5 0

Distribute the outside number (the 2 fractions in this case) to the numbers in the parenthesis. Multiply them and then solve for the variable. To solve for variable just add or subtract the constant (add if negative subtract if positive). Then divide each side with the number paired with the variable.

Just ask if you want me to edit answers in

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If a random sample of size nequals=6 is taken from a​ population, what is required in order to say that the sampling distributio
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Answer:

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.

Step-by-step explanation:

For this case we have that the sample size is n =6

The sample man is defined as :

\bar X = \frac{\sum_{i=1}^n X_i}{n}

And we want a normal distribution for the sample mean

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

In order to satisfy this distribution we need that each observation on this case comes from a normal distribution, because since the sample size is not large enough we can't apply the central limit theorem.

So for this case we need to satisfy the following condition:

X_i \sim N(\mu , \sigma), i=1,2,...,n

Because if we find the parameters we got:

E(\bar X) =\frac{1}{n} \sum_{i=1}^n E(X_i) = \frac{n\mu}{n}=\mu

Var(\bar X)= \frac{1}{n^2} \sum_{i=1}^n Var(X_i) = \frac{n\sigma^2}{n^2}= \frac{\sigma^2}{n}

And the deviation would be:

Sd (\bar X) = \frac{\sigma}{\sqrt{n}}

And we satisfy the condition:

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

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Step-by-step explanation:

The point A is located at (-5, -7), as shown in the graph. The x-coordinate is -5,  and the y-coordinate is -7.

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Answer:

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6,300 divide by 900 would equal 7

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Answer:

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Step-by-step explanation:

If she already had 9 grapes, subtract 15 and 9 to get 6.

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