The work done in pushing the box is 64000 lb-ft²/s²
<h3>How to calculate the work done by the person?</h3>
Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is
W = mgh where
- m = mass of box = 40 lb,
- g = acceleration due to gravity = 32 ft/s² and
- h = height of incline = LsinФ where
- L = length of incline = 100 ft and
- Ф = angle of incline = 30°
So, W = mgh
W = mgLsinФ
So, substituting the values of the variables into the equation, we have
W = mgLsinФ
W = 40 lb × 32 ft/s² × 100 ftsin30°
W = 1280 lb-ft/s² × 100 ft × 0.5
W = 1280 lb-ft/s² × 50 ft
W = 64000 lb-ft²/s²
So, the work done in pushing the box is 64000 lb-ft²/s²
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To get the distance DC we proceed as follows:
AB-CD
=11-3
=8
BC=15
hence using Pythagorean theorem
c²=a²+b²
c=DC
a=BC
b=8
thus
c²=15²+8²
c²=225+64
c²=289
thus
c=√289
c=17 units
Answer: B. 17 units
The most right answer would be the one you think because I think that’s right 4x4
Tan -1 = 13/21
31.7
32degrees
<h3>
Answer: <u>
100 ft</u>
is the hypotenuse</h3>
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Work Shown:
a = 60 and b = 80 are the two known sides
c is the unknown hypotenuse
Applying the pythagorean theorem gets us...
a^2 + b^2 = c^2
60^2 + 80^2 = c^2
3600 + 6400 = c^2
10,000 = c^2
c^2 = 10,000
c = sqrt(10,000)
c = 100
A quick way to see that 100 ft is the missing side is to note that a 6,8,10 right triangle scales up to 60,80,100 after multiplying all three sides by 10.
Or you could start with a 3,4,5 right triangle and multiply all three sides by 20.