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djyliett [7]
3 years ago
12

Solve this math problem -2 1/3-(-5)= ​

Mathematics
2 answers:
bazaltina [42]3 years ago
7 0
2 2/3 , 2.6 repeating, or 8/3
dmitriy555 [2]3 years ago
4 0

Answer:

8/3 or 2.6 repeating

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the answer is c:  7 feet 7 inches

Step-by-step explanation:

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What is the slope of a line parallel to the line whose equation is
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y=6x-14

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Let T:ℝ2→ℝ2 be the linear transformation that first rotates points clockwise through 45∘ (????/4 radians) and then reflects poin
Alisiya [41]

Answer:

T = \left[\begin{array}{ccc}-\frac{1}{\sqrt{2} } &\frac{1}{\sqrt{2} }\\\frac{1}{\sqrt{2} }&\frac{1}{\sqrt{2} }\end{array}\right]

Step-by-step explanation:

Let General Transformation matrix be denoted as T

Step 1: Clockwise rotation of 45 degrees

General counterclockwise rotation matrix in 2-dimension is given as

                                        R(\theta)=\left[\begin{array}{ccc}cos\theta & - sin\theta\\sin\theta&cos\theta\\\end{array}\right]

For clockwise rotation we need to insert θ as negative in the above matrix. Therefore, the resulting matrix is

                                        R(-\theta)=\left[\begin{array}{ccc}cos\theta & sin\theta\\-sin\theta&cos\theta\\\end{array}\right]

as sin(-θ) = -sin (θ) and cos(-θ) = cos (θ)

For 45 degrees

sin(45)  = \frac{1}{\sqrt{2} }   and   cos(45)  = \frac{1}{\sqrt{2} }

                                       R(-45)=\left[\begin{array}{ccc}\frac{1}{\sqrt{2} }  & \frac{1}{\sqrt{2} }\\-\frac{1}{\sqrt{2} }&\frac{1}{\sqrt{2} }\\\end{array}\right]

Step 2: Reflection through line y = x

This type of reflection maps (x,y)→(y,x)

Therefore the general matrix is

                                           R(x,y)=\left[\begin{array}{ccc}0&1\\1&0\end{array}\right]

Step 3: General Transformation Matrix

T = R(x,y) R(-θ)

                                    T=\left[\begin{array}{ccc}0&1\\1&0\end{array}\right] \left[\begin{array}{ccc}\frac{1}{\sqrt{2} }  & \frac{1}{\sqrt{2} }\\-\frac{1}{\sqrt{2} }&\frac{1}{\sqrt{2} }\\\end{array}\right]

                                           T = \left[\begin{array}{ccc}-\frac{1}{\sqrt{2} } &\frac{1}{\sqrt{2} }\\\frac{1}{\sqrt{2} }&\frac{1}{\sqrt{2} }\end{array}\right]

3 0
3 years ago
Crystal Rollerbladed 150 feet in 15 seconds, while Gavin rollerbladed 150 feet in 10 seconds. Without doing any calculations, wh
mario62 [17]

Answer: Gavin was faster because his time was less than Crystal's.

Step-by-step explanation: They rollerbladed the same distance but Gavin did it in less time.

Hope this helped!

Mark Brainliest if you want!

3 0
3 years ago
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Find the missing side of the right triangle where c is the hypotenuse and a and b are
Vlada [557]

Answer: 10.2

Step-by-step explanation:

b = 15² - 11²

= 225 - 121

= 104

= √104

= 10.2

8 0
3 years ago
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