Answer:
you have a 7/12 chance
Step-by-step explanation:
The sample space has 12 elements:
T1, T2, T3, T4, T5, T6
H1, H2, H3, H4, H5, H6
(From a combinatorics perspective, there are 2 options for the coin and 6 for the die for a total of 2 * 6 = 12.)
There are 6 heads results and one tales result that has a 4 for a total of 7 possibilities that meet your criteria. That makes the probability 7 / 12.
here is the link for where i got my answer https://www.quora.com/If-you-flip-a-coin-and-roll-a-die-what-is-the-probability-the-coin-lands-heads-up-or-the-die-lands-showing-the-number-4
Answer:
y = 4x - 8
Step-by-step explanation:
(-1, -12) & (4, 8)
First you want to find the slope of the line that passes through these points. To find the slope of the line, we use the slope formula: (y₂ - y₁) / (x₂ - x₁)
Plug in these values:
(8 - (-12)) / (4 - (-1))
Simplify the parentheses.
= (8 + 12) / (4 + 1)
= (20) / (5)
Simplify the fraction.
20/5
= 4
This is your slope. Plug this value into the standard slope-intercept equation of y = mx + b.
y = 4x + b
To find b, we want to plug in a value that we know is on this line: in this case, I will use the second point (4, 8). Plug in the x and y values into the x and y of the standard equation.
8 = 4(4) + b
To find b, multiply the slope and the input of x(4)
8 = 16 + b
Now, subtract 16 from both sides to isolate b.
-8 = b
Plug this into your standard equation.
y = 4x - 8
This is your equation.
Check this by plugging in the other point you have not checked yet (-1, -12).
y = 4x - 8
-12 = 4(-1) - 8
-12 = -4 - 8
- 12 = -12
Your equation is correct.
Hope this helps!
pls zoom up!!!!!!!!!!!!!!!!!!!!!!
Step-by-step explanation:
I'll help you as soon as possible
Step-by-step explanation:
37,7m, π*(r*2)
r*2 is diameter it's kinda ez , just put 37,7m and ur done
<h3>Answer:</h3>
(x, y) ⇒ (-y, x)
<h3>Explanation:</h3>
A point at y=1 on the y-axis will rotate to the point x = -1 on the x-axis when it is rotated 90° CCW about the origin. Hence the value of x for the image point is the opposite of the y-value of the original point.
A point at x=1 on the x-axis will rotate to the point y=1 on the y-axis when it is rotated 90° CCW about the origin. Hence the value of y for the image point is the x-value of the original point.
In summary, ...
... (x, y) ⇒ (-y, x)
_____
<em>Comment on rotation matrices</em>
The rotation matrix for rotatation through the angle θ CCW about the origin is ...
![\left[\begin{array}{cc}\cos{(\theta)}&-\sin{(\theta)}\\\sin{(\theta)}&\cos{(\theta)}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Ccos%7B%28%5Ctheta%29%7D%26-%5Csin%7B%28%5Ctheta%29%7D%5C%5C%5Csin%7B%28%5Ctheta%29%7D%26%5Ccos%7B%28%5Ctheta%29%7D%5Cend%7Barray%7D%5Cright%5D)
When θ = 90°, this matrix becomes ...
![\left[\begin{array}{cc}0&-1\\1&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0%26-1%5C%5C1%260%5Cend%7Barray%7D%5Cright%5D)
and multiplication by coordinates (x, y) gives ...
![\left[\begin{array}{cc}0&-1\\1&0\end{array}\right]\times\left[\begin{array}{c}x\\y\end{array}\right] = \left[\begin{array}{c}-y\\x\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D0%26-1%5C%5C1%260%5Cend%7Barray%7D%5Cright%5D%5Ctimes%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D-y%5C%5Cx%5Cend%7Barray%7D%5Cright%5D)
