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3 years ago

Please help me. I need to finish this!

Mathematics

1 answer:

kkurt [141]3 years ago

3 0

Answer:

3x + 19 = 10x - 23

7x = 42

X = 6

180 - (2×37) = 106

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Membership in the Volunteers Club increased by 15% from last year. If the number of members last year was m, complete a simplifi

ad-work [718]

For this case what you can do is the following rule of three:
m ---> 100%
x ----> 115%
Clearing the value of x we have:
x = (115/100) * (m)
x = 1.15 * (m)
Answer:
a simplified expression to represent the number of members this year is:
x = 1.15 * (m)

4 0

4 years ago

Please help me out and with work included

irina1246 [14]

Hope that makes sense

3 0

3 years ago

The ages of three cousins are consecutive even whole numbers. The sum of the youngest and oldest is 16. How old is the oldest co

PilotLPTM [1.2K]

The oldest cousin should be 10. If their ages are consecutive even whole numbers, then the younger cousins should be 2 & 4. 2+4=6+10=16

4 0

3 years ago

Need help will mark Brainliest

Svetach [21]

Answer:

250 ft.

Step-by-step explanation:

It seems that you are learning the side-splitter theorem right now. If a line is parallel to one side of the triangle and intersects the other two sides, it divides the side proportionally. From the picture we can tell that the streets are parallel, with a line of intersection. Therefore, we can create the following equation of proportionality:

$\frac{375}{300} = \frac{x}{200}$

Now that we have this equation, we can use the butterfly method to solve for x. We cross multiply:

$375*200=300x\\$

Now, all we have to do is isolate the variable to find x:

$75000=300x\\x=250$

Therefore, the distance of Orange Ave between the 3rd St. and 4th St. is 250 ft.

I hope this helps! Please let me know if you have any further questions :)

5 0

3 years ago

The sum of the first 5 terms of an AP is 30 and the sum of the four term from T6 to T9 (inclusive) is 69. Find the AP

Ainat [17]

Answer: The AP = 1, ⁷/₂, 6, ¹⁷/₂, 11 ..............

Step-by-step explanation:

From the first statement,

S₅ = ⁵/₂(2a + ( n - 1 )d } = 30

5(2a + 4d )d = 60

10a + 20d = 60

reduce to lowest term to easy calculation by dividing through by 10

a + 2d = 6 -----------------------------------1

second statement

sum of the next 4 terms inclusive

T₉ = ⁹/₂(2a + 8d ) = 69

9(2a + 8d ) = 30 + 69

18a + 72d = 99 x 2

18a + 72d = 198

divide through by 18 to reduce to lowest time

a + 4d = 11 ------------------------------------------2

Now solve the two equation simultaneously to find a and d

a + 2d = 6

a + 4d = 11

-2d = -5

d = ⁵/₂.

Now substitute for d to get a

a + 2(⁵/₂) = 6

a + 5 = 6

a = 6 - 5

a = 1.

Therefore the AP = 1 , ⁷/₂ , 6 , ¹⁷/₂ , 11 , ..............

7 0

3 years ago