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2 years ago

How many presents are between 40_45 years old

Mathematics

2 answers:

elena-14-01-66 [18.8K]2 years ago

8 0

The answer would be 2 hope this helps

maksim [4K]2 years ago

3 0

Answer:

9 im guessing because 40 years old is 2 and 45 is 7 it stands in the middle then add and you get that

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Hi can you help me pleaseeee?)

olganol [36]

<em>So to solve for a variable, you have to isolate that variable onto one side.</em>

Firstly, multiply both sides by j: $h-4=kj$

Next, divide both sides by k and <u>your answer will be: $\frac{h-4}{k}=j$ </u>

Firstly, add g on both sides: $\frac{x}{5}=a+g$

Next, multiply both sides by 5 and <u>your answer will be: $x=5(a+g)$ </u>

Firstly, subtract 5p on both sides: $9c=-4p$

Next, divide both sides by 9 and <u>your answer will be $c=-\frac{4}{9}p$ </u>

3 0

3 years ago

QUESTION 7<br> Solve for x.<br> (3x + 32)<br> (5x-8)<br> O a. 3<br> b. 12<br> O c. 20<br> O d. 19.5

Alchen [17]

Answer:

The answer is x = 20

Step-by-step explanation:

If you set both equations equal to each other and solve for x, you will get 20.

3x+32 = 5x-8 add 8 to both sides

3x+40 = 5x subtract 3x from both sides

40 = 2x divide by 2 on both sides

20 = x

7 0

3 years ago

Chau's shop sells quarts of ice cream each day. How much is this in pints?

barxatty [35]

Answer:

One quart is 2 pints

Step-by-step explanation:

multiply the number of quarts by 2 to get the number of pints.

5 0

3 years ago

Is k6= a solution or non solution

mrs_skeptik [129]

I think it will be a solution. Hope it help!

6 0

3 years ago

Read 2 more answers

Find the volume of the following solid. The solid between the cylinder f(x,y)equals=e Superscript negative xe−x and the region

PilotLPTM [1.2K]

It is hard to comprehend your question. As far as I understand:

f(x,y) = e^(-x)

Find the volume over region R = {(x,y): 0<=x<=ln(6), -6<=y <= 6}.

That is all I understood. It would be easier to understand with a picture or some kind of visual aid.

Anyways, to find the volume between the surface and your rectangular region R, we must evaluate a double integral of f on the region R.

$\iint_{R}^{ } e^{-x}dA=\int_{-6}^{6} \int_{0}^{ln(6)} e^{-x}dx dy$

Now evaluate,

$\int_{0}^{ln(6)}e^{-x}dx$

which evaluates to, 5/6 if I did the math correct. Correct me if I am wrong.

Now integrate this w.r.t. y:

$\int_{-6}^{6}\frac{5}{6}dy = 10$

So,

$\iint_{R}^{ } e^{-x}dA=\int_{-6}^{6} \int_{0}^{ln(6)} e^{-x}dx dy = 10$

7 0

3 years ago

How many presents are between 40_45 years old ​

How many presents are between 40_45 years old