The first step to solve this problem is to represent
variables for the width and the length:
Let w = width of the rectangle
2w – 1 = length
of the rectangle
The formula to compute for the area of the rectangle is:
A = LW
Substituting the values and variables to the formula:
28 = w (2w – 1)
2w^2 – w = 28
2w^2 – w – 28 = 0
Solve the quadratic equation:
(2w + 7)(w – 4) = 0
w = -7/2 or w = 4
You cannot use the -7/2 because there is no negative
measurement.
W = 4 feet
L = 2(4) – 1 = 7 feet
Therefore the dimension of the rectangle is 4 feet by 7
feet.
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Answer:
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Step-by-step explanation:
Question:
Expand and simplify 5(x - 1) - 3(x + 4)
Answer:
1.) Use the distributive property to solve this equation:
5(x - 1) = 5x - 5
3(x + 4) = 3x + 12
2.) Put it in the equation:
5x - 5 - 3x + 12
3.) Group them:
5x - 3x - 5 + 12
4.) Simplify:
2x - 7
which is the answer.
Hope this helped! :))
4 students in each row (key word "each" meaning multiply) since there are only 11 rows completely filled that means you multiply 4 and 11 which equals 44, plus the 2 students in the 12th row equals 46.
4×11=44+2=46
