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3 years ago

A triangular bandana has an area of 54 square inches. The height of the triangle is

Mathematics

1 answer:

Nonamiya [84]3 years ago

5 0

Answer:

The base is 3 inches

Step-by-step explanation:

A = 1/2bh

54 = 1/2(36)b

54 = 18b

b = 3

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Write the equation that represents the relationship between n the number of triangles and p the perimeter of the figures formed.

Klio2033 [76]

1 triangle: 2*6 + 1*5

2 triangles: 2*6 + 2*5

3 triangles: 2*6 + 3*5

So for n triangles: p = 2*6 + n*5 = 12 + 5n

4 0

3 years ago

Read 2 more answers

−5y+3x=3<br> −8y+9x=−12<br> <br> What is X and Y please.

Tomtit [17]

Answer:

( -4, -3 )

Step-by-step explanation:

Let's solve by elimination. Reason being there are no variables without coefficients.

−5y+3x=3 Multiply equation by 3. Each term.

−8y+9x=−12

-15y + 9x = 9 Subtract the to equations

-8y + 9x = -12

___________

-7y = 21

y = -3

Substitute y into original equation

-5(-3) + 3x = 3

15 + 3x = 3 Subtract 15 both sides

3x = -12 Divide by 3, both sides

x = -4

4 0

3 years ago

Read 2 more answers

Please help me figure this out for me!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

nordsb [41]

Pretty sure its B but if im wrong please dont be mad.

7 0

3 years ago

Show do i solve for the missing answers

BARSIC [14]

(g + f)(x)
g(x) + f(x)
x - 1 + x^2 + 4
x^2 + x + 3

(g - h)(x)
g(x) - h(x)
3x + 1 - (2x - 2)
3x + 1 - 2x + 2
x + 3

5 0

2 years ago

David’s bank offers a 36-month Certificate of Deposit (CD) with an APR of 2.25%. Use the compound interest formula to answer the

tamaranim1 [39]

Using compound interest, it is found that:

a) A(8) = 2389.66

b) t = 31.15

c) P = 1870.85

Compound interest:

$A(t) = P\left(1 + \frac{r}{n}\right)^{nt}$

A(t) is the amount of money after t years.
P is the principal(the initial sum of money).
r is the interest rate(as a decimal value).
n is the number of times that interest is compounded per year.
t is the time in years for which the money is invested or borrowed.

In this problem:

The APR is of 2.25%, hence $r = 0.0225$ .

No information about the number of compounding per year, hence $n = 1$ .

Item a:

$P = 2000$ , hence:

$A(t) = P\left(1 + \frac{r}{n}\right)^{nt}$

$A(8) = 2000\left(1 + \frac{0.0225}{1}\right)^{8}$

$A(8) = 2389.66$

Item b:

$A(t) = 4000$ , hence:

$A(t) = P\left(1 + \frac{r}{n}\right)^{nt}$

$4000 = 2000\left(1 + \frac{0.0225}{1}\right)^{t}$

$(1.0225)^t = 2$

$\log{(1.0225)^t} = \log{2}$

$t\log{1.0225} = \log{2}$

$t = \frac{\log{2}}{\log{1.0225}}$

$t = 31.15$

Item c:

$A(3) = 2000$ , hence:

$A(t) = P\left(1 + \frac{r}{n}\right)^{nt}$

$2000 = P\left(1 + \frac{0.0225}{1}\right)^{3}$

$P = \frac{2000}{(1.0225)^3}$

$P = 1870.85$

A similar problem is given at brainly.com/question/24850750

7 0

2 years ago