Answer:
56
Step-by-step explanation:
First, I drew picture of a line containing points W and Z.
Next, I added a midpoint between W and Z and labelled it Y.
Next, I added a midpoint between W and Y and labelled it X.
It is given that XY = 14, so that means WX is also 14 (because X is the midpoint, these two distances have to the be the same)
Now I know WY is 28, which means YZ is also 28.
So WZ has to be 56.
He missed all the other words ( if I’m wrong I’m sorry that’s what the research told me )
Hmmm, as I read it, in year 1, but it doesn't say at the beginning of the year or end, so we'll be assuming is at the beginning of year 1, the amount is 850, how much will it be at the beginning of year 6? namely, 5 years later.
![\bf ~~~~~~ \textit{Simple Interest Earned Amount}\\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\to& \$850\\ r=rate\to 8\%\to \frac{8}{100}\to &0.08\\ t=years\to &5 \end{cases} \\\\\\ A=850[1+0.08(5)]\implies A=850(1.4)](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~%20%5Ctextit%7BSimple%20Interest%20Earned%20Amount%7D%5C%5C%5C%5C%0AA%3DP%281%2Brt%29%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0AA%3D%5Ctextit%7Baccumulated%20amount%7D%5C%5C%0AP%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cto%26%20%5C%24850%5C%5C%0Ar%3Drate%5Cto%208%5C%25%5Cto%20%5Cfrac%7B8%7D%7B100%7D%5Cto%20%260.08%5C%5C%0At%3Dyears%5Cto%20%265%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0AA%3D850%5B1%2B0.08%285%29%5D%5Cimplies%20A%3D850%281.4%29)
Answer:
You have to equal the unit first,
as 1 Rupee = 100 paise,
so,
55paise: 100paise,
= 11:20
I hope it hepled : )
Answer:
First question: Choice A
second question:Choice D
Third question: Choice c
Fourth question: Choise b
5th Question: choice b
