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vredina [299]
3 years ago
9

Hellpppppppppppppppp memeeeeeeeee

Mathematics
1 answer:
blondinia [14]3 years ago
8 0

Answer:

S

R

T

P

Q

Step-by-step explanation:

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Help out due this week
gladu [14]

Answer:

i dont even know what congruent means

Step-by-step explanation:

step 1 throw your hands up then point them to the floor!

step 2 here is what to do now get down on all fours!

step 3 now bounce around its easy follow me!

step 4 go crazy now and beep beep like a sheep

5 0
3 years ago
What is the product in scientific notation?
sashaice [31]
(2.5 × 10^{-10} ) × (7 × 10^{-6} )

First, simplify brackets. / Your problem should look like: 2.5 × 10^{-10} × 7 × 10^{-6}
Second, simplify. / Your problem should look like: 17.5 × 10^{-10} × 10^{-6}
Third, simplify exponent. / Your problem should look like: 17.5 × 10^{-15}

Answer: B

3 0
3 years ago
Read 2 more answers
Which statement about rational numbers is true?
Kamila [148]

Answer:

All fractions contain integers and rational numbers

have a nice day

4 0
3 years ago
Read 2 more answers
The value of a classic car is given by
egoroff_w [7]

Answer:

the answer is c

Step-by-step explanation:

you add sub mult and divide it's math it's simple

3 0
3 years ago
How many solutions does this equation have
larisa86 [58]

Answer:

Two solutions

Step-by-step explanation:

This is a quadratic equation in the form y = ax² + bx + c.

For quadratic equations, you can find solutions using the quadratic formula:

x = \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

To find the number of solutions, <u>you only need what's inside the square root</u>. We call it the "<u>discriminant</u>" because lets us know the number of solutions without solving.

b^{2}-4ac

If b²- 4ac > 0, two solutions. (greater than)

If b²- 4ac < 0, no solutions. (less than)

If b²- 4ac = 0, one solution. (equal to)

y = ax² + bx + c

y = -3x² + x + 12

a = -3   b = 1   c = 12

<u>Substitute into the discriminant</u>

b²- 4ac

= 1² - 4(-3)(12)

= 1 - (-144)

= 145 > 0

b²- 4ac > 0                Discriminant greater than 0

Therefore, there are two solutions.

7 0
3 years ago
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