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soldier1979 [14.2K]
3 years ago
10

Which of the following is the fastest computer processing speed?

Computers and Technology
1 answer:
vodomira [7]3 years ago
6 0
Answer: Gigahertz

Explanation: One megahertz is equal to one million cycles per second, while one gigahertz equals one billion cycles per second.

This means a 1.8 GHz processor has twice the clock speed of a 900 MHz processor.
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Variance for accumulator. Validate that the following code, which adds the
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Using the knowledge of computational language in JAVA it is possible to write a code that Validate that the following code, which adds the methods var() and stddev() to Accumulator, computes both the mean and variance of the numbers presented as arguments to addDataValue()

<h3>Writting the code:</h3>

<em>import java.util.*;</em>

<em>public class </em><em>Accumulator </em><em>{  </em>

<em>private static double m;   </em>

<em>private static double v;   </em>

<em>private static double st;   </em>

<em>private static  double s[]=new double[5]; </em>

<em>private static int N;</em>

<em>private static int count =0;</em>

<em>public static void main(String[] args) {</em>

<em>// TODO Auto-</em><em>generated </em><em>method stub</em>

<em>Random r = new Random();</em>

<em>System.out.println("hello world");</em>

<em>for(int i=0;i<5;i++) {</em>

<em>    double randomvalue = r.nextDouble();</em>

<em>addDataValue(randomvalue);</em>

<em>}</em>

<em>for(int i=0;i<s.length;i++) {</em>

<em>    System.out.println("dataValue:"+s[i]);</em>

<em>}   </em>

<em>mean();</em>

<em>System.out.println("mean:"+m);</em>

<em>var();</em>

<em>System.out.println("variance:"+v);</em>

<em>stddev();</em>

<em>System.out.println("standard deviation:"+st);</em>

<em>}</em>

<em>public  static void </em><em>addDataValue</em><em>(double value) {     // addes data values to array</em>

<em>  s[count]=value;</em>

<em>  count++;</em>

<em> }</em>

<em>public static double mean() {        // returns mean</em>

<em>double sum=0.0;</em>

<em>for(int i=0;i<s.length;i++) {</em>

<em>    sum+=s[i];</em>

<em>}</em>

<em>m = sum/s.length;</em>

<em> return m;</em>

<em>}   </em>

<em>public </em><em>static </em><em>double var() {    //returns variance</em>

<em>double mm = mean();</em>

<em>     double t = 0;</em>

<em>     for(int i=0;i<s.length;i++) {</em>

<em>         t+= (s[i]-mm)*(s[i]-mm);</em>

<em>} </em>

<em>     v= t/(s.length-1);</em>

<em>      return v;  </em>

<em>}</em>

<em>public static  double </em><em>stddev</em><em>() {        // returnsn the stardard deviation </em>

<em>st= Math.sqrt(var());</em>

<em>return st;</em>

<em>}</em>

<em>}</em>

See more about JAVA at brainly.com/question/12975450

#SPJ1

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Answer:

It is all true.

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