The sum of twice a number and 4 times another number is 4. The difference of the numbers is 5. Find the numbers(help a sis out)
1 answer:
Answer:
1st number = 4
2nd number = -1
Step-by-step explanation:
Let n = 1st number
Let m = 2nd number
2n + 4m = 4
n - m = 5
Substitu method, let n = 5 + m
2(5+m) + 4m = 4
10 + 2m + 4m = 4
6m = -6
m = -1
find n:
n - (-1) = 5
n + 1 = 5
n = 4
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Sorry I don’t see the question how am supposed to answer it