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ololo11 [35]
3 years ago
15

Help!please do this fast!!!

Mathematics
2 answers:
JulsSmile [24]3 years ago
4 0

Answer:

The ordered pair works for the first equation on the top, but not the second equation on the bottom.

Step-by-step explanation:

You have to plug in the x and y values into the equations:

x - 2y = -6

2 - 2(4) = -6  

That equation works.

...now for the next one...

3x + 2y = 12

3(2) + 2(4) = 12

That equation doesn't work.

Hope this helps!

sasho [114]3 years ago
4 0
It is not because when you plug x=2 and y=4 into the second equation, it is not a true statement. In order for the ordered pair to apply to the system, there needs to be a true statement for BOTH equations not just the first one.

Observe:

2-2(4)=-6
-6=-6 this is a true statement

3(2)-2(4)=12
6-8=12
-2≠12 this is a false statement

Therefore the solution 2,4 doesn’t apply to the system since it only applies to one of the equations
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To get to the other side of the lake, one can drive around it on Lake Road, go over the bridge or ride the ferry. How many diffe
Alexus [3.1K]
The answer is 9, here are all the possible combinations...

road, road
road, bridge
road, ferry
bridge, bridge
bridge, ferry
bridge, road
ferry, ferry
ferry, bridge
ferry, boat

(or you can do 3 input combinations by 3 output combinations "3 x 3" = 9)

Cheers!
8 0
3 years ago
Read 2 more answers
What is the difference?
Serhud [2]

Answer:

The option \frac{(x+5)(x+2)}{x^3-9x} is correct

The difference of the given expression is

\frac{2x+5}{x^2-3x}-(\frac{3x+5}{x^3-9x})-({\frac{x+1}{x^2-9})=\frac{(x+5)(x+2)}{x^3-9x}

Step-by-step explanation:

Given expression is \frac{2x+5}{x^2-3x}-(\frac{3x+5}{x^3-9x})-({\frac{x+1}{x^2-9})

To find the difference of the given expression as below :

\frac{2x+5}{x^2-3x}-(\frac{3x+5}{x^3-9x})-({\frac{x+1}{x^2-9})

=\frac{2x+5}{x(x-3)}-(\frac{3x+5}{x(x^2-9)})-({\frac{x+1}{x^2-9})

=\frac{2x+5}{x(x-3)}-(\frac{3x+5}{x(x^2-3^2)})-({\frac{x+1}{x^2-3^2})

=\frac{2x+5}{x(x-3)}-(\frac{3x+5}{x(x-3)(x+3)})-({\frac{x+1}{(x-3)(x+3)})  

( using the formula a^2-b^2=(a+b)(a-b) )

=\frac{2x+5(x+3)-(3x+5)-x(x+1)}{x(x-3)(x+3)}

=\frac{2x^2+6x+5x+15-3x-5-x^2-x}{x(x-3)(x+3)} (adding the like terms)

=\frac{x^2+7x+10}{x(x^2-9)} ( by factoring the quadratic polynomial )

=\frac{(x+5)(x+2)}{x^3-9x}

Therefore \frac{2x+5}{x^2-3x}-(\frac{3x+5}{x^3-9x})-({\frac{x+1}{x^2-9})=\frac{(x+5)(x+2)}{x^3-9x}

Therefore the difference of the given expression is

\frac{(x+5)(x+2)}{x^3-9x}

Therefore option \frac{(x+5)(x+2)}{x^3-9x} is correct

8 0
3 years ago
What is the y intercept
Diano4ka-milaya [45]
Y intercept is (0, -4/5)
Set x as 0 and solve
Ignore the dumb kid who said y=8
3 0
3 years ago
6x-42x<br><br>will give brainliest!!!
scoray [572]
<span><span>Step by step :

6x</span>−<span>42x</span></span><span>
=<span><span><span>6x</span>+</span>−<span>42x</span></span></span>
<span>=<span><span>6x</span>+<span>−<span>42x</span></span></span></span><span>
=<span>(<span><span>6x</span>+<span>−<span>42x</span></span></span>)</span></span><span>
=<span>−<span>36x</span></span></span>
Hoped I helped!
4 0
3 years ago
Read 2 more answers
0.7 expressed as a percentage is
klemol [59]
It’s 70% because I just know
3 0
3 years ago
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