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Leno4ka [110]
3 years ago
12

PLEASE PLEASE HELP ME QUICK!!!!

Mathematics
2 answers:
Sati [7]3 years ago
4 0

Answer:

u have a solid line...means there is an equal sign in the problem...so that eliminates 2 of them right away...so A and D are incorrectit is shaded below the line....this means it is less then...that eliminates option C leaving u with only one answer choiceso ur answer is : B. y is less then or equal to x

Step-by-step explanation:

Greeley [361]3 years ago
3 0
U have a solid line...means there is an equal sign in the problem...so that eliminates 2 of them right away...so A and D are incorrect

it is shaded below the line....this means it is less then...that eliminates option C leaving u with only one answer choice

so ur answer is : B. y is less then or equal to x
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Stephanie and Susan were counting the money from their lemonade stand Stephanie sold 4 times more glasses of lemonade than Susan
kolbaska11 [484]

Answer

Stephanie sold 40 glasses while Susan sold 10 glasses

Step-by-step explanation:

Stephanie sold 4 times more glasses than Susan, overall of 50 glasses

3 0
2 years ago
Help<br> ================
creativ13 [48]

Answer:

Step-by-step explanation:

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6 0
2 years ago
In a study of the accuracy of fast food drive-through orders, McDonald’s had 33 orders that were not accurate among 362 orders o
melomori [17]

Answer:

A. We need to conduct a hypothesis in order to test the claim that the true proportion of inaccurate orders p is 0.1.

B. Null hypothesis:p=0.1  

Alternative hypothesis:p \neq 0.1  

C. z=\frac{0.0912 -0.1}{\sqrt{\frac{0.1(1-0.1)}{362}}}=-0.558  

D. z_{\alpha/2}=-1.96  z_{1-\alpha/2}=1.96

E. Fail to the reject the null hypothesis

F. So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion of inaccurate orders is not significantly different from 0.1.  

Step-by-step explanation:

Data given and notation

n=362 represent the random sample taken

X=33 represent the number of orders not accurate

\hat p=\frac{33}{363}=0.0912 estimated proportion of orders not accurate

p_o=0.10 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

A: Write the claim as a mathematical statement involving the population proportion p

We need to conduct a hypothesis in order to test the claim that the true proportion of inaccurate orders p is 0.1.

B: State the null (H0) and alternative (H1) hypotheses

Null hypothesis:p=0.1  

Alternative hypothesis:p \neq 0.1  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

C: Find the test statistic

Since we have all the info required we can replace in formula (1) like this:  

z=\frac{0.0912 -0.1}{\sqrt{\frac{0.1(1-0.1)}{362}}}=-0.558  

D: Find the critical value(s)

Since is a bilateral test we have two critical values. We need to look on the normal standard distribution a quantile that accumulates 0.025 of the area on each tail. And for this case we have:

z_{\alpha/2}=-1.96  z_{1-\alpha/2}=1.96

P value

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(z  

E: Would you Reject or Fail to Reject the null (H0) hypothesis.

Fail to the reject the null hypothesis

F: Write the conclusion of the test.

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the true proportion of inaccurate orders is not significantly different from 0.1.  

6 0
3 years ago
How many pennies are in a tower with a height of 0 cm
Yuri [45]
There would be no pennies
4 0
3 years ago
In 2007, a census counted 2815 of a certain animal. This was 315 fewer than the number counted in 2006. What was the population
Irina-Kira [14]

Answer: 3,130

Step-by-step explanation: 2,815 + 315 = 3,130

7 0
3 years ago
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