Complete the synthetic division problem below.
1 answer:
You might be interested in
Answer:
Given: A parallelogram EFGH in which diagonals intersect at point J.
To Find: A segment congruent to EJ.
Solution: In parallelogram EFGH
Point of intersection of Diagonals EG and FH are point J.
As we know diagonals of parallelogram bisect each other.
So, EJ=JG and FJ=JH
∵ Solution is EJ≅ JG
ON = 8x • 8
LM = 7x + 4
NM = x - 5
OL = 3y - 6
OL is congruent & parallel to NM
LM is congruent & parallel to ON
So,
Simplify
subtract 7x from both sides
divide 57 from both sides
Substitute x into equations
NM & OL = -28/57
ON & LM = 4 + (28/57)
LM = 7x + 4
NM = x - 5
OL = 3y - 6
OL is congruent & parallel to NM
LM is congruent & parallel to ON
So,
Simplify
subtract 7x from both sides
divide 57 from both sides
Substitute x into equations
NM & OL = -28/57
ON & LM = 4 + (28/57)