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3 years ago

A family of 12 went to the local Italian restaurant for dinner. Every family member

Mathematics

2 answers:

egoroff_w [7]3 years ago

7 0

Answer:

4a + 8d = 12

I hope this helps you

mojhsa [17]3 years ago

4 0

12c + 3a + 6d = total bill when d stands for dessert and a stands for appitizer and 12 stands for drinks and meals

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a normal distribution has a mean of 10 and a standard deviation of 1 what is the probability of selecting a number between 8 and

rusak2 [61]

Answer:

0.815

Step-by-step explanation:

First, find the z-scores.

z = (x − μ) / σ

z₁ = (8 − 10) / 1

z₁ = -2

z₂ = (11 − 10) / 1

z₂ = 1

P(-2 < Z < 1) = P(Z < 1) − P(Z < -2)

Use a chart, calculator, or the empirical rule to find the probability.

Using the empirical rule:

P(-2 < Z < 1) = 0.84 − 0.025

P(-2 < Z < 1) = 0.815

Using a chart:

P(-2 < Z < 1) = 0.8413 − 0.0228

P(-2 < Z < 1) = 0.8185

5 0

4 years ago

What is the value of x in this figure? Enter your answer in the box. x = The figure contains a pair intersecting lines. One angl

alexandr1967 [171]

It would be 78 degrees because the angle opposite of it is the vertical angle, and vertical angles are congruent to each other.

4 0

3 years ago

Read 2 more answers

Do you think that civilians should be targeted in warfare? Why or why not?

jasenka [17]

When countries are at war, the general rule is that civilians should not be targeted and I <u>support </u>this notion.

<h3>The Concept of War</h3>

War is fought by nations to assert dominance and achieve certain conditions.
War is fought by soldiers who pick of weapons to engage in war.

Civilians should therefore not be targeted because they have not picked up weapons to engage in the fight and so cannot be said to be targets. It makes no sense to leave the person you are fighting and who wants to fight you, to fight those who are not interested in fighting.

In conclusion, civilians should not be targeted.

Find out more on targeting civilians at brainly.com/question/261234.

6 0

2 years ago

Arrange the cones in order from lease volume to greatest volume

bearhunter [10]

Answer:

Volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

cone with DIAMETER of 18 & height of 10

cone with RADIUS of 10 & height of 9

cone with RADIUS of 11 & height of 9

cone with DIAMETER of 20 & height of 12

Step-by-step explanation:

Let $V_{2}. V_{3}. and\ V_{4}.$ be the volume of the cone.

Let d, r and h be the diameter, radius and height of the cone.

Given:

$d_{1} = 20\ and\ h_{1}=12$

$d_{2} = 18\ and\ h_{2}=10$

$r_{3} = 10\ and\ h_{3}=9$

$r_{4} = 11\ and\ h_{14}=9$

Arrange the cones in order from lease volume to greatest volume.

Solution:

The volume of the cone is given below.

$V=\pi r^{2} \frac{h}{3}$ ----------------(1)

where: r is radius of the base of cone.

and h is height of the cone.

The volume of the cone for $d_{1} = 20\ and\ h_{1}=12$

$r_{1} = \frac{d_{1}}{2}$

$r_{1} = \frac{20}{2}=10\ units$

$V_{1}=\pi (r_{1})^{2} \frac{h_{1}}{3}$

$V_{1}=\pi (10)^{2} \frac{12}{3}$

$V_{1}=\pi\times 100\times 4$

$V_{1}=400\pi\ units^{3}$

Similarly, for volume of the cone for $d_{2} = 18\ and\ h_{2}=10$

$r_{2} = \frac{d_{2}}{2}$

$r_{2} = \frac{18}{2}=9\ units$

$V_{2}=\pi (r_{2})^{2} \frac{h_{2}}{3}$

$V_{2}=\pi (9)^{2} \frac{10}{3}$

$V_{2}=\pi\times 81\times \frac{10}{3}$

$V_{2}=\pi\times 27\times 10$

$V_{2}=270\pi\ units^{3}$

Similarly, for volume of the cone for $r_{3} = 10\ and\ h_{3}=9$

$V_{3}=\pi (r_{3})^{2} \frac{h_{3}}{3}$

$V_{3}=\pi (10)^{2} \frac{9}{3}$

$V_{3}=\pi\times 100\times 3$

$V_{3}=\pi\times 300$

$V_{3}=300\pi\ units^{3}$

Similarly, for volume of the cone for $r_{4} = 11\ and\ h_{4}=9$

$V_{4}=\pi (r_{4})^{2} \frac{h_{4}}{3}$

$V_{4}=\pi (11)^{2} \frac{9}{3}$

$V_{4}=\pi\times 121\times 3$

$V_{4}=\pi\times 363$

$V_{4}=363\pi\ units^{3}$

So, the volume of the cone in ascending order.

$V_{2}=270\pi\ units^{3}$

7 0

3 years ago

Rewrite with only sin x and cos x. sin 2x - cos x

morpeh [17]

$\bf sin(2\theta)=2sin(\theta)cos(\theta)\\\\
-------------------------------\\\\
sin(2x)-cos(x)\implies 2sin(x)cos(x)-cos(x)
\\\\\\
cos(x)[2sin(x)-1]$

3 0

3 years ago

Read 2 more answers