Question

Identify the number and type of solutions for the equation 3x2 − 5x + 19 = 0.

Answer 1

Answer:

$x=\frac{5\±i√203}{6}$(the lanky a is a square root)

Step-by-step explanation:

I suppose the equation is $3x^2-5x+19=0$?

A good old quadratic equation! Back to the good old days when we are memorizing the formula...

$x=\frac{-b\±√(b^2-4ac)}{2a}$

(Yes that little lanky a is a square root)

$x=\frac{-(-5)\±√((-5)^2-4(3)(19))}{2(3)} \\x=\frac{5\±√(25-228)}{6}\\x=\frac{5\±√-203}{6} \\x=\frac{5\±i√203}{6}$

Since the discriminant is negative, there are no real solutions, but instead, we have complex solutions shown above.